ytg

joined 9 months ago
[–] [email protected] 12 points 5 months ago* (last edited 5 months ago)

English spelling doesn't match sound, it's about sound

European is (depending on exact dialect) /ˌjoː.ɹəˈpɪ.jan/, so it begins with a consonant. So you don't need "an"

[–] [email protected] 1 points 5 months ago

Using "Next"

So true! I can also confirm it happens cross-linguistically

[–] [email protected] 5 points 5 months ago

Hey, we have the same profile picture!

[–] [email protected] 2 points 5 months ago (2 children)

Surely the US government won't like that if they're US citizens, right?

[–] [email protected] 6 points 5 months ago* (last edited 5 months ago) (1 children)

that can’t stop giving her money

well… I mean… you don't have to

[–] [email protected] 0 points 5 months ago* (last edited 5 months ago) (1 children)

For any a, b, c, if a = b and b = c, then a = c, right? The transitive property of equality.
For any a, b, x, if a = b, then x + a = x + b. The substitution property.
By combining both of these properties, for any a, b, x, y, if a = b and y = b + x, it follows that b + x = a + x and y = a + x.

In our example, a is x' (notice the ') and b is 0.999… (by definition). y is 10x' and x is 9. Let's fill in the values.

If x' = 0.9999… (true by definition) and 10x = 0.999… + 9 (true by algebraic manipulation), then 0.999… + 9 = x' + 9 and 10x' = x' + 9.

if you are rearranging algebra you have to do the exact same thing on both sides

If you actually change any of the sides. Since, after substitution, the numeric value doesn't change (literally the definition of equality), I don't have to do anything – as I'm not rearranging. I'm merely presenting the same value in an equivalent manner. By contrast, when multiplying both sides by 10, since multiplication by 10 changes the concrete numeric value, I have to do it on both sides to maintain the equality relation (ditto for subtracting x'). But substitution never changes a numeric value – only rearranges what we already know.


(Edit)

Take the following simple system of equations.

5y = 3
x + y = 6

How would you solve it? Here's how I would:

\begin{gather*} %% Ignore the LaTeX boilerplate, just so I could render it
\begin{cases}
y = \frac{3}{5} \\ % Isolate y by dividing both sides by 5
x = 6 - y % Subtract y from both sides
\end{cases} \\
x = 6 - \frac{3}{5} \\ % SUBSTITUTE 3/5 for y
x = 5.4 \\
(x, y) = (5.4, 0.6)
\end{gather*}

Here's how Microsoft Math Solver would do it.

[–] [email protected] 0 points 5 months ago (4 children)

The substitution property of equality is a part of its definition; you can substitute anywhere.

[–] [email protected] 6 points 5 months ago

The choice is obvious to you. Not to the average American.

[–] [email protected] 6 points 6 months ago (2 children)

[…] until we wake up and Kemi Badenoch doesn’t exist anymore […]

Just an unfortunate choice of words. It would have been easy to foresee how this could be interpreted. That doesn't mean she's right, though.

Also, does anyone have a proper definition of optics (in this context)? I've heard this word a lot, but I still don't quite understand it

[–] [email protected] 24 points 6 months ago (13 children)

Similarly, 1/3 = 0.3333…
So 3 times 1/3 = 0.9999… but also 3/3 = 1

Another nice one:

Let x = 0.9999… (multiply both sides by 10)
10x = 9.99999… (substitute 0.9999… = x)
10x = 9 + x (subtract x from both sides)
9x = 9 (divide both sides by 9)
x = 1

[–] [email protected] 1 points 6 months ago

North Korea: 316 downloads

[–] [email protected] 24 points 6 months ago (7 children)

Interesting that an Israeli newspaper provides a more balanced report than US outlets… how did that happen?

view more: ‹ prev next ›