this post was submitted on 20 Apr 2025
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chapotraphouse

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[–] [email protected] 25 points 1 week ago* (last edited 1 week ago) (2 children)

Yeah if Earth’s gravity is 9.8 m/s^2^, I think that would mean a planet twice the mass would have a gravity of ~96m/s^2^. Correct me if I’m wrong physicist hexbears.

Edit: upon cursory reading it seems much more complicated than this. Basically the force needed to leave the gravitational pull doesn’t necessarily directly correlate to the gravity exerted by the object, size and distance are involved too

[–] [email protected] 15 points 1 week ago* (last edited 1 week ago)

Twice the mass is twice force twice the acceleration. Gravitational force is linear to the mass of one of the objects. It would be 19.6m/s2 if the radius was the same but the radius is larger and that's inverse quadratic. Double the radius, quarter the acceleration. Although I really doubt that planet is only double our mass.

2.6x the radius of earth, 8.63±1.35 the mass of earth.

[–] [email protected] 1 points 1 week ago

Fg=G(m_1 * m_2)/r^2