this post was submitted on 14 Jun 2024
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2024-11-11

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A new study by astrophysicist Richard Lieu suggests that gravity can exist without mass, proposing thin, shell-like layers of 'topological defects' as an alternative to dark matter for explaining the gravitational binding of galaxies. This theory posits that these defects create a gravitational force without detectable mass, potentially eliminating the need for dark matter in current cosmological models

Lieu started out trying to find another solution to the Einstein field equations, which relate the curvature of space-time to the presence of matter within it. As Einstein described in his 1915 theory of general relativity, space-time warps around bundles of matter and streams of radiation in the Universe, depending on their energy and momentum. That energy is, of course, related to mass in Einstein's famous equation: E=mc2. So an object's mass is linked to its energy, which bends space-time -- and this curvature of space-time is what Einstein described as gravity, a notch more sophisticated than Newton's 17th-century approximation of gravity as a force between two objects with mass. In other words, gravity seems inextricably linked to mass. Not so, posits Lieu.

In his workings, Lieu set about solving a simplified version of the Einstein field equations that allows for a finite gravitation force in the absence of any detectable mass. He says his efforts were "driven by my frustration with the status quo, namely the notion of dark matter's existence despite the lack of any direct evidence for a whole century." Lieu's solution consists of shell-shaped topological defects that might occur in very compact regions of space with a very high density of matter. These sets of concentric shells contain a thin layer of positive mass tucked inside an outer layer of negative mass. The two masses cancel each other out, so the total mass of the two layers is exactly zero. But when a star lies on this shell, it experiences a large gravitational force dragging it towards the center of the shell. "The contention of my paper is that at least the shells it posits are massless," Lieu says. If those contentious suggestions bear any weight, "there is then no need to perpetuate this seemingly endless search for dark matter," Lieu adds.

The next question, then, is how to possibly confirm or refute the shells Lieu has proposed through observations. "The increasing frequency of sightings of ring and shell-like formation of galaxies in the Universe lends evidence to the type of source being proposed here," Lieu writes in his paper. Although he admits that his proposed solution is "highly suggestive" and cannot alone discredit the dark matter hypothesis. "It could be an interesting mathematical exercise at best," Lieu concludes. "But it is the first [mathematical] proof that gravity can exist without mass."

The study has been published in Monthly Notices of the Royal Astronomical Society.

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[–] [email protected] 7 points 5 months ago (1 children)

Okay, so hear me out here before shouting me down:

This is just kind of thinking "around" the lack of observable Dark Matter, the fact that we haven't detected any massive gravitational oddities when relating to mass, and the Einstein Field Equations. So it's just kind of replacing the 'm' in the equation, but wouldn't we be detecting this sort of thing literally everywhere by now? How would this justify something observable like Gravitational Redshift, because it would seem we would have noticed something like this for as long as we've had deep space telescopes, no?

[–] [email protected] 2 points 5 months ago (2 children)

I don't understand any of this so this question isn't snarky but something I'm actually wondering. How would we be able to see "topological defects" in space with telescopes?

[–] [email protected] 2 points 5 months ago (1 children)

Gravitational Redshift has been confirmed and observed. If there was a whole bunch of the gravity spheres just out in space hanging out, it seems we would have been able to confirm that similarly by observing large swaths of distorted space and red shifted light waves.

[–] [email protected] 2 points 5 months ago (1 children)

Isn't the point of this that it explains the phenomena that is commonly attributed to dark matter? Therefore wouldn't the things we observe that would point to this be the same things that we observe that point to dark matter? I guess the thing I don't understand is why we would expect to observe something different because of this than what we attribute to dark matter.

[–] [email protected] 0 points 5 months ago

This is a reimagining of e=mc2, without the m. It attempts to explain gravity and missing mass, but with these spheres instead of mass. Skips Dark Matter.

[–] [email protected] 2 points 5 months ago* (last edited 5 months ago) (1 children)

I am not an expert either, but maybe by something like this? Maybe we see two images of the same galaxy but nothing obstructing our view to explain the gravitational lensing, so maybe it's topological defects?

[–] [email protected] 1 points 5 months ago* (last edited 5 months ago)

Hmm, I'm not sure how to correctly word my question.

It was really just aimed at the implication in the comment I replied to that if this were true, we should have seen evidence for it in telescopes already. So my question was, what phenomena would we expect to see because of these topological defects that we don't already see and have attributed to dark matter.

As far as I'm aware (which really isn't that far tbh) gravitational lensing is explained without needing any new hypotheses. But if dark matter was implicated in it to heighten the effect, that would still be something we have seen in our telescopes which could be explained by this so it still would answer the comment to which I replied as being something we have observed.

Edit: OK I looked it up and yeah dark matter (or another explanation) is required to account for the amount of lensing we see. But still, that's a thing we have observed so I guess my question would be, does this new idea not account for the same effect? If it does, that should answer the comment I was replying to.