i++ (programming.dev)

submitted 2 years ago by [email protected] to c/[email protected]

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[-] [email protected] 0 points 2 years ago

Isn't the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn't it be more correct to make it equal to ++i

[-] [email protected] 0 points 2 years ago

In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.

So, this would be a compiler error:

a = (x=3)

[-] [email protected] 1 points 2 years ago

Well, not all languages allow for fun programming :)

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this post was submitted on 19 Jun 2023

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