Takes 1 more character, that's bloat.
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I saw while(i --> 0) in someone else's code and thought wth is this --> operator? Then I realized it's while(i-- > 0) and thought cool, I gotta do this!
Isn't the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn't it be more correct to make it equal to ++i
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And that's why post- and pre-increment is non-existant in Python and Rust. It's an easy source for bugs for a noncritical abbreviation🤷
In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.
So, this would be a compiler error:
a = (x=3)
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