Programmer Humor

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i++ (programming.dev)

submitted 1 year ago by [email protected] to c/[email protected]

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[–] [email protected] 0 points 1 year ago (2 children)

Isn't the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn't it be more correct to make it equal to ++i

[–] [email protected] 0 points 1 year ago (1 children)

In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.

So, this would be a compiler error:

a = (x=3)

[–] [email protected] 1 points 1 year ago

Well, not all languages allow for fun programming :)

[–] [email protected] 0 points 1 year ago (1 children)

And that's why post- and pre-increment is non-existant in Python and Rust. It's an easy source for bugs for a noncritical abbreviation🤷

[–] [email protected] -1 points 1 year ago

They're especially also a source of bugs, because they encourage manually incrementing indices and manually accessing array positions, which is almost never actually sensible.