this post was submitted on 22 Aug 2024
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It must be a silent R (lemmy.world)
submitted 4 weeks ago by [email protected] to c/[email protected]
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[–] [email protected] 11 points 3 weeks ago (4 children)

"strawberry".split('').filter(c => c === 'r').length

[–] [email protected] 9 points 3 weeks ago (1 children)

len([c if c == 'r' for c in "strawberry"])

[–] [email protected] 6 points 3 weeks ago

'strawberry'.match(/r/ig).length

[–] [email protected] 2 points 3 weeks ago

(\r (frequencies "strawberry"))