[–] 8 points 6 months ago (2 children)

@scruiser there's no winning with these guys. I had a similar experience with someone bringing up South Korea as an example of country that brought itself up by its bootstraps via unfettered capitalism because “planned economy doesn't work”, so I had to remind them that SK was a military dictatorship who implemented 5-year plans leveraging billions of foreign investment that was given to it by US to prop it up against NK.

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  • [–] 2 points 7 months ago

    @RetroHax @Auster @gog

    Arguably it's because they can't ensure the same (or higher) level of compatibility with newer versions of dosbox or scummvm (e.g. because of regressions). It's still possible to use newer dosbox/scummvm with the games they provide by hacking around the launcher and/or just using the installation elseways, but it would be nice if this was supported at the installation package level.

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  • [–] 4 points 7 months ago

    @Jarix oh, that, yeah. GOG is currently in a decent position because it has a launcher, but it's basically a “thin layer” on top of APIs that allow anyone to download the installers (plus some services to manage those installations). As long as the underlying APIs remain accessible, it's fine. (This is e.g. how lgogdownloader allows one to archive their whole library for offline installation.)

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    A curious math problem I came up with: given a target, what's the fewest digits an integer must have (in a given base) to contain all integers from 0 to the target, as substrings?

    http://wok.oblomov.eu/mathesis/number-substrings/

    @mathematics @math@lemmy.ml @math@kbin.social

    e.g. for a target of 19 a candidate representative would be 1011213141516171819 in base 10, that has 19 digits. Can it be done in less, or is $\sigma_10(19) = 19$?
    Can we find a general rule? Any properties of this function?

    #math #maths #numberTheory #combinatorics

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