milon

joined 2 years ago
[–] [email protected] 1 points 6 days ago (1 children)

The idiom allowed it to pass the checker's tests! Thanks for your help!

[–] [email protected] 2 points 6 days ago

That passed the test! Thank you!

[–] [email protected] 1 points 1 week ago* (last edited 1 week ago) (9 children)

It's for CS50P which uses a customized VS Code. It has an automated code checker which I ran when I was done.

outputs "Just right!" when guess is correct

timed out while waiting for program to exit

[–] [email protected] 1 points 1 week ago (5 children)

Was using tabs but I went through it to make sure and seemed to be ok.

25
submitted 1 week ago* (last edited 1 week ago) by [email protected] to c/[email protected]
 

There is an issue with the program when the user correctly guesses the number. The program should end when the break statement executes in the while loop found in main(), but instead it times out.

import random


def main():
    level = get_level()
    number = generate_random_number(level)

    while True:
        guess = get_guess()

        if check_guess(number, guess) == False:
            continue
        else:
            break


def get_level():
    while True:
        level = input("Level: ")

        try:
            int(level)
        except ValueError:
            continue
        if int(level) <= 0:
            continue
        else:
            return int(level)

def generate_random_number(level):
    number = random.randint(1, level)

    return number

def get_guess():
    while True:
        guess = input("Guess: ")

        try:
            int(guess)
        except ValueError:
            continue
        if int(guess) <= 0:
            continue
        else:
            return int(guess)

def check_guess(number, guess):
    if guess > number:
        print("Too large!")

        return False
    if guess < number:
        print("Too small!")

        return False
    if guess == number:
        print("Just right!")

        return True


main()
[–] [email protected] 2 points 2 weeks ago

Yeah I think I will follow the same approach. 3rd parties are a bit risky.

[–] [email protected] 1 points 2 weeks ago (2 children)

Thanks for the additional info. Maybe I will opt for the developer version instead in that case.

[–] [email protected] 1 points 2 weeks ago

Yup no issues here

[–] [email protected] 2 points 2 weeks ago

I see now. So it's possible for someone to run into multiple issues which can make updating a hassle.

[–] [email protected] 2 points 2 weeks ago (4 children)
[–] [email protected] 2 points 2 weeks ago (2 children)

Yes, I did. I was warned about doing so before but now I understand 😆

[–] [email protected] 2 points 2 weeks ago

Turns out the issue was with one or some of the layered packages I had. After uninstalling, the CLI method to upgrade worked. See the post below, but thanks for your reply.

21
submitted 2 weeks ago* (last edited 2 weeks ago) by [email protected] to c/[email protected]
 

I am trying to update from Silverblue 41 to 42 (fully updated) but run into issues when attempting to update from both the software app and from CLI.

The problem using the software app is the same as what is described by this other user, who is using Fedora Workstation not Silverblue like I am:

https://discussion.fedoraproject.org/t/update-to-fedora-42-fails-in-gnome-software/148885

When I click the download button, it looks like it's downloading multiple files since the progress bar goes from 0 to 100 several times, and then it gets up to 95% then suddenly returns to the download button. This happens in about 30 seconds.

Using the CLI method, I run the following command:

rpm-ostree rebase fedora:fedora/42/x86_64/silverblue

and get the following errors:

 Problem: conflicting requests
  - package dnf5-plugin-automatic-5.2.12.0-2.fc42.x86_64 from updates requires libcurl-full(x86-64), but none of the providers can be installed
  - package dnf5-plugin-automatic-5.2.12.0-1.fc42.x86_64 from fedora requires libcurl-full(x86-64), but none of the providers can be installed
  - package dnf5-plugin-automatic-5.2.12.0-2.fc42.x86_64 from updates-archive requires libcurl-full(x86-64), but none of the providers can be installed
  - package libcurl-minimal-8.11.1-4.fc42.x86_64 from @System conflicts with libcurl(x86-64) provided by libcurl-8.11.1-4.fc42.x86_64 from fedora

SOLUTION: Uninstalled layered packages in dnf-automatic, libreoffice, and rpmfusion and then restarted. Rebase command successfully completed thereafter.

3
submitted 3 weeks ago* (last edited 2 weeks ago) by [email protected] to c/[email protected]
 

.

 

if coin == 25 | 10 | 5:

If I replace the '|' with 'or' the code runs just fine. I'm not sure why I can't use '|' in the same statement.

Doing the following doesn't work either:

if coin == 25 | coin == 10 | coin == 5:

I know bitwise operators can only be used with integers, but other then that is there another difference from logical operators?

21
submitted 2 months ago* (last edited 2 months ago) by [email protected] to c/[email protected]
 
 # Ask user to enter an expression and display output
def main():
    expression = input("Expression: ")

    print(calculate(splitter(expression)))


# Split expression into components and assign to variables as float values
def splitter(expression):
    x, y, z = expression.split()

    return x, y, z

# Calculate expression result
def calculate(x, y, z):
    x, z = float(x), float(z)

    if y == "+":
        return str(round((x + z), 1))
    elif y == "-":
        return str(round((x - z), 1))
    elif y == "*":
        return str(round((x * z), 1))
    else:
        return str(round((x / z), 1))



main()

I am getting traceback errors for any expression (1 + 1) I enter.

 

I used the debugger to examine this code but not understanding a couple areas.

  1. Why does the for loop repeat after it exits to print a new line? If it exits the loop, shouldn't it be done with it?
  2. Why is n incremented and not i as stated with i++?

int main(void)
{
    int height = get_int("Height: ");

    draw(height);
}

void draw(int n)
{
    if (n &lt;= 0)
    {
        return;
    }

    draw(n - 1);

    for (int i = 0; i &lt; n; i++)
    {
        printf("#");
    }
    printf("\n");
}
 

This is in C language. When I call rotate() in main, the function returns false for isalpha() even though the string entered for plaintext uses alphabetic characters. Perhaps it's identifying an alphabetic character by its ASCII value ('A' = 65)? I tried to test that out and used (char) with the letter variable in rotate() but it didn't change anything.

PORTION OF MAIN

string plaintext = get_string("plaintext:  ");

    int length = strlen(plaintext);
    char ciphertext[length];

    for (int i = 0; i &lt; length; i++)
    {
        ciphertext[i] = rotate(plaintext[i], key);
    }

ROTATE FUNCTION

char rotate(char letter, int key)
{
    if (isalpha(letter) == true)
    { ...
 

In VS I am told this function "does not return a value in all control paths." A bot told me specifically the issue is with this line: else if (letter + key <= 90). It said that if the outcome results in letter + key equally exactly 90 then a value is not returned, but I thought that was covered where '<=' means 'less than or equals.'

char rotate(char letter, int key)
{
    if (isalpha(letter) == true)
    {
        if (letter + key > 90)
        {
            int overage = letter + key - 90;
            letter = 64 + overage;

            while (letter > 90)
            {
                overage = letter - 90;
                letter += overage;
            }

            return letter;
        }

        else if (letter + key &lt;= 90)
        {
            letter += key;
            return letter;
        }
    }

    else if (isalpha(letter) == false)
    {
        return letter;
    }
13
submitted 2 years ago* (last edited 2 years ago) by [email protected] to c/[email protected]
 

What is %.2f? Why is it not just %f? Is there some additional calculation happening? The half function already does all the calculations including splitting the bill, so I'm not sure what %.2f is. (Btw why is this code not formatting correctly in lemmy?)


#include 
#include 

float half(float bill, float tax, int tip);

int main(void)
{
    float bill_amount = get_float("Bill before tax and tip: ");
    float tax_percent = get_float("Sale Tax Percent: ");
    int tip_percent = get_int("Tip percent: ");

    printf("You will owe $%.2f each!\n", half(bill_amount, tax_percent, tip_percent));
}

// TODO: Complete the function
float half(float bill, float tax, int tip)
{
    bill += (bill * (tax / 100.0));
    bill += (bill * (tip / 100.0));

    bill /= 2;

    return bill;
}
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