you are missing a returning else block.
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This particular compiler isn't smart enough to recognize that isalpha(letter) == true and isalpha(letter) == false are mutually exclusive conditions. It thinks there's a third scenario that you haven't accounted for.
That's because they're not necessarily mutually exclusive. The function is being called twice so there's no way to guarantee the result will be the same both times without knowing what it does under the hood.
Consider a case where isalpha performs a coin flip, 50% chance each call to return true. The first call returns false so the first condition fails, then the second call returns true so the second condition fails; in 25% of cases neither code block executes.
You could store the result of the first call in a local variable and reuse it if you really wanted to, but the smart solution is to either use if/else properly or switch to early returns instead.
Right, the compiler isn't smart enough to recognize that isalpha() is pure and deterministic.
Expect isalpha is part of the standard library not an arbitrary function, a compile should be able to optimize standard calls.
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