I'm assuming he is disabled. It looks like there are three marked handicap spaces. The way you want him to park, two additional vehicles with side ramps could park. A total of 3 handicap vehicles, 2 with side ramps.

The way he actually parked, two vehicles with side ramps could park (both utilizing the other ramp space, one pulling in, the other backing in), and another handicapped space is still available for a vehicle without side ramps, which are the overwhelming majority of handicapped vehicles. A total of 4 handicap vehicles, 2 with side ramps.

Now, I admit, my arithmetic skills were developed before the era of "New Math", so they might have changed it since. But when I learned it, "4" was greater than "3".