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Rule (lemmy.blahaj.zone)

submitted 3 weeks ago by [email protected] to c/[email protected]

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[–] [email protected] 5 points 3 weeks ago (1 children)

i hate to bring this up, but we also need a separate function for negative numbers

[–] [email protected] 1 points 3 weeks ago

You can just bitwise AND those with ...000000001 (for however many bits are in your number). If the result is 0, then the number is even, and if it's 1, then the number is odd. This works for negative numbers because it discards the negative signing bit.