this post was submitted on 02 Dec 2024
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Advent Of Code

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Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2024

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Day 2: Red-Nosed Reports

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FAQ

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[–] [email protected] 9 points 3 weeks ago (1 children)

Haskell

This was quite fun! I got a bit distracted trying to rewrite safe in point-free style, but I think this version is the most readable. There's probably a more monadic way of writing lessOne as well, but I can't immediately see it.

safe xs = any gradual [diffs, negate <$> diffs]
  where
    diffs = zipWith (-) (drop 1 xs) xs
    gradual = all (`elem` [1 .. 3])

lessOne [] = []
lessOne (x : xs) = xs : map (x :) (lessOne xs)

main = do
  input :: [[Int]] <- map (map read . words) . lines <$> readFile "input02"
  print . length $ filter safe input
  print . length $ filter (any safe . lessOne) input
[–] [email protected] 4 points 3 weeks ago (3 children)

Love to see your haskell solutions!

I am so far very amazed with the compactness of your solutions, your lessOne is very much mind-Bending. I have never used or seen <$> before, is it a monadic $?

Also I can't seem to find your logic for this safety condition: The levels are either all increasing or all decreasing, did you figure that it wasn't necessary?

[–] [email protected] 3 points 3 weeks ago

For the last point, it isn't needed since the differences between elements should be all positive or all negative for the report to be safe. This is tested with the combination of negate and gradual.

I am also enjoying these Haskell solutions. I'm still learning the language, so it's been cool to compare my solution with these and grow my understanding of Haskell.

[–] [email protected] 2 points 3 weeks ago* (last edited 3 weeks ago)

<$> is just fmap as an infix operator.

>>> fmap (+1) [1,2,3]
[2,3,4]
>>> (+1) <\$> [1,2,3]
[2,3,4]
[–] [email protected] 1 points 3 weeks ago

Thanks! The other two posters already answered your questions, I think :)

Haskell makes it really easy to build complex operations out of simple functional building blocks, skipping a lot of boilerplate needed in some other languages. I find the compactness easier to read, but I realize that not everyone would agree.

BTW, I'm a relative Haskell newbie. I'm sure more experienced folks could come up with even more interesting solutions!

[–] [email protected] 5 points 3 weeks ago

Haskell

runningDifference :: [Int] -> [Int]
runningDifference (a:[]) = []
runningDifference (a:b:cs) = a - b : (runningDifference (b:cs))

isSafe :: [Int] -> Bool
isSafe ds = (all (> 0) ds || all (< 0) ds) && (all (flip elem [1, 2, 3] . abs) ds) 

isSafe2 :: [Int] -> Bool
isSafe2 ds = any (isSafe2') (zip [0..length ds] (cycle [ds]))

isSafe2' (i, ls) = isSafe . runningDifference $ list
        where
                list = dropIndex i ls

dropIndex _ []     = []
dropIndex 0 (a:as) = dropIndex (-1) as
dropIndex i (a:as) = a : dropIndex (i - 1) as

main = do
        c <- getContents
        let reports = init . lines $ c
        let levels  = map (map read . words) reports :: [[Int]]
        let differences = map runningDifference levels
        let safety = map isSafe differences
        let safety2 = map isSafe2 levels

        putStrLn . show . length . filter (id) $ safety
        putStrLn . show . length . filter (id) $ safety2

        return ()

Took me way too long to figure out that I didn't have to drop one of them differences but the initial Number

[–] [email protected] 5 points 3 weeks ago* (last edited 3 weeks ago) (2 children)

Uiua

Uiua is still developing very quickly, and this code uses the experimental tuples function, hence the initial directive.

Try it Live!

# Experimental!
"7 6 4 2 1\n1 2 7 8 9\n9 7 6 2 1\n1 3 2 4 5\n8 6 4 4 1\n1 3 6 7 9"
⊜(βŠœβ‹•βŠΈβ‰ @\s)βŠΈβ‰ @\n # Partition at \n, then at space, parse ints.

IsSorted ← +βŠƒ(β‰β‡Œβ†.|≍⍆.)        # Compare with sorted array.
IsSmall  ← /Γ—Γ—βŠƒ(>0|<4)βŒ΅β†˜Β―1-↻1. # Copy offset by 1, check diffs.
IsSafe   ← Γ—βŠƒIsSmall IsSorted  # Safe if Small steps and Ordered.
IsSafer  ← Β±/+≑IsSafe β§…<-1⧻.   # Choose 4 from 5, check again.

&p/+≑IsSafe .            # Part1 : Is each row safe?
&p/+≑(Β±+βŠƒIsSafe IsSafer) # Part2 : Is it safe or safer?
[–] [email protected] 7 points 3 weeks ago (2 children)

How do you write this, not conceptually but physically. Do you have a char picker open at all times?

[–] [email protected] 4 points 3 weeks ago

Haha, you can do it that way, in fact the online Uiua Pad editor has all the operators listed along the top.

But all the operators have ascii names, so you can type e.g. IsSmall = reduce mul mul fork(>0|<4) abs drop neg 1 - rot 1 dup and the formatter will reduce that to IsSmall ← /Γ—Γ—βŠƒ(>0|<4)βŒ΅β†˜Β―1-↻1. whenever you save or execute code.

That works in the Pad, and you can enable similar functionality in other editors.

[–] [email protected] 2 points 3 weeks ago (1 children)

i can only imagine doing it with a drawing tablet

[–] [email protected] 4 points 3 weeks ago

I like to assume people using array programming languages just have a crystal ball that they use to call upon magic runes on the screen

[–] [email protected] 3 points 3 weeks ago (1 children)

This looks so alien! Does it work with the full set? The comment says 5, choose 4, but I guess it’s written as n, choose n-1?

[–] [email protected] 1 points 3 weeks ago

Yes, it should do. I do run the solutions against the live data, but sometimes tweak the solutions afterwards, so can't always guarantee them :-). I left the comment as 5 choose 4 as it felt clearer in the context of the test data.

It does still feel very alien at times, but I do love being able to think about how to adopt a more arrays-based approach to solving these problems.

[–] [email protected] 5 points 3 weeks ago (1 children)

C

First went through the input in one pass, number by number, but unfortunately that wouldn't fly for part 2.

Code

#include "common.h"

static int
issafe(int *lvs, int n, int skip)
{
	int safe=1, asc=0,prev=0, ns=0,i;

	for (i=0; safe && i<n; i++) {
		if (i == skip)
			{ ns = 1; continue; }
		if (i-ns > 0)
			safe = safe && lvs[i] != prev &&
			    lvs[i] > prev-4 && lvs[i] < prev+4;
		if (i-ns == 1)
			asc = lvs[i] > prev;
		if (i-ns > 1)
			safe = safe && (lvs[i] > prev) == asc;

		prev = lvs[i];
	}

	return safe;
}

int
main(int argc, const char **argv)
{
	char buf[64], *rest, *tok;
	int p1=0,p2=0, lvs[16],n=0, i;

	if (argc > 1)
		DISCARD(freopen(argv[1], "r", stdin));

	while ((rest = fgets(buf, sizeof(buf), stdin))) {
		for (n=0; (tok = strsep(&rest, " ")); n++) {
			assert(n < (int)LEN(lvs));
			lvs[n] = (int)strtol(tok, NULL, 10);
		}

		for (i=-1; i<n; i++)
			if (issafe(lvs, n, i))
				{ p1 += i == -1; p2++; break; }
	}

	printf("02: %d %d\n", p1, p2);
}

https://github.com/sjmulder/aoc/blob/master/2024/c/day02.c

[–] [email protected] 2 points 3 weeks ago (1 children)

What is this coding style? The function type, name and open brace placement made me think GNU at first, but the code in the body doesn't look like GCS at all.

[–] [email protected] 2 points 3 weeks ago

BSD more or less. Mostly K&R except for function declarations.

[–] [email protected] 5 points 3 weeks ago (2 children)

Rust

The function is_sorted_by on Iterators turned out helpful for compactly finding if a report is safe. In part 2 I simply tried the same with each element removed, since all reports are very short.

fn parse(input: String) -> Vec<Vec<i32>> {
    input.lines()
        .map(|l| l.split_whitespace().map(|w| w.parse().unwrap()).collect())
        .collect()
}

fn is_safe(report: impl DoubleEndedIterator<Item=i32> + Clone) -> bool {
    let safety = |a: &i32, b: &i32| (1..=3).contains(&(b - a));
    report.clone().is_sorted_by(safety) || report.rev().is_sorted_by(safety)
}

fn part1(input: String) {
    let reports = parse(input);
    let safe = reports.iter().filter(|r| is_safe(r.iter().copied())).count();
    println!("{safe}");
}

fn is_safe2(report: &[i32]) -> bool {
    (0..report.len()).any(|i| {  // Try with each element removed
        is_safe(report.iter().enumerate().filter(|(j, _)| *j != i).map(|(_, n)| *n))
    })
}

fn part2(input: String) {
    let reports = parse(input);
    let safe = reports.iter().filter(|r| is_safe2(r)).count();
    println!("{safe}");
}

util::aoc_main!();
[–] [email protected] 2 points 3 weeks ago

is_sorted_by is new to me, could be very useful.

[–] [email protected] 2 points 3 weeks ago

The is_sorted_by is a really nice approach. I originally tried using that function thinking that |a, b| a > b or |a, b| a < b would cut it but it didn't end up working. I never thought to handle the check for the step being between 1 and 3 in the callback closure for that though.

[–] [email protected] 4 points 3 weeks ago* (last edited 3 weeks ago)

Nim

Got correct answer for part 1 on first try, but website rejected it. Wasted some time debugging and trying different methods. Only to have the same answer accepted minutes later. =(

proc isSafe(report: seq[int]): bool =
  let diffs = collect:
    for i, n in report.toOpenArray(1, report.high): n - report[i]
  (diffs.allIt(it > 0) or diffs.allIt(it < 0)) and diffs.allIt(it.abs in 1..3)

proc solve(input: string): AOCSolution[int, int] =
  let lines = input.splitLines()
  var reports: seq[seq[int]]
  for line in lines:
    reports.add line.split(' ').map(parseInt)

  for report in reports:
    if report.isSafe():
      inc result.part1
      inc result.part2
    else:
      for t in 0..report.high:
        var mReport = report
        mReport.delete t
        if mReport.isSafe():
          inc result.part2
          break

Codeberg repo

[–] [email protected] 4 points 3 weeks ago

Of course I ended up with a off-by-one error for the second part, so things took a bit longer than they really should've.

But either way, behold, messy C#:

C#

int[][] reports = new int[0][];

public void Input(IEnumerable<string> lines)
{
  reports = lines.Select(l => l.Split(' ').Select(p => int.Parse(p)).ToArray()).ToArray();
}

public void Part1()
{
  int safeCount = reports.Where(report => CheckReport(report)).Count();
  Console.WriteLine($"Safe: {safeCount}");
}
public void Part2()
{
  int safeCount = reports.Where(report => {
    if (CheckReport(report))
      return true;

    for (int i = 0; i < report.Length; ++i)
      if (CheckReport(report.Where((_, j) => j != i)))
        return true;

    return false;
  }).Count();

  Console.WriteLine($"Safe: {safeCount}");
}

bool CheckReport(IEnumerable<int> report)
{
  var diffs = report.SkipLast(1).Zip(report.Skip(1)).Select(v => v.Second - v.First);
  return diffs.All(v => Math.Abs(v) <= 3) && (diffs.All(v => v > 0) || diffs.All(v => v < 0));
}

[–] [email protected] 4 points 3 weeks ago* (last edited 3 weeks ago)

#Rust

initially, for part two I was trying to ignore a bad pair not a bad value - read the question!

Only installed Rust on Sunday, day 1 was a mess, today was more controlled. Need to look at some of the rust solutions for std library methods I don't know about.

very focussed on getting it to actually compile/work over making it short or nice!

long!`

pub mod task_2 {

pub fn task_1(input: &str) -> i32{
    let mut valid_count = 0;

    let reports = process_input(input);

    for report in reports{
        let valid = is_report_valid(report);

        if valid{
            valid_count += 1;
        }
    }

    println!("Valid count: {}", valid_count);
    valid_count
}

pub fn task_2(input: &str) -> i32{
    let mut valid_count = 0;

    let reports = process_input(input);

    for report in reports{
        let mut valid = is_report_valid(report.clone());

        if !valid
        {
            for position_to_delete in 0..report.len()
            {
                let mut updated_report = report.clone();
                updated_report.remove(position_to_delete);
                valid = is_report_valid(updated_report);

                if valid { break; }
            }
        }

        if valid{
            valid_count += 1;
        }
    }

    println!("Valid count: {}", valid_count);
    valid_count
}

fn is_report_valid(report:Vec<i32>) -> bool{
    let mut increasing = false;
    let mut decreasing = false;
    let mut valid = true;

    for position in 1..report.len(){
        if report[position-1] > report[position]
        {
            decreasing = true;
        }
        else if report[position-1] < report[position]
        {
            increasing = true;
        }
        else
        {
            valid = false;
            break;
        }

        if (report[position-1] - report[position]).abs() > 3
        {
            valid = false;
            break;
        }

        if increasing && decreasing
        {
            valid = false;
            break;
        }
    }

    return valid;
}

pub fn process_input(input: &str) -> Vec<Vec<i32>>{
    let mut reports: Vec<Vec<i32>> = Vec::new();
    for report_string in input.split("\n"){
        let mut report: Vec<i32> = Vec::new();
        for value in report_string.split_whitespace() {
            report.push(value.parse::<i32>().unwrap());
        }
        reports.push(report);
    }

    return reports;
}

}

`

[–] [email protected] 4 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

Factor

: get-input ( -- reports )
  "vocab:aoc-2024/02/input.txt" utf8 file-lines
  [ split-words [ string>number ] map ] map ;

: slanted? ( report -- ? )
  { [ [ > ] monotonic? ] [ [ < ] monotonic? ] } || ;

: gradual? ( report -- ? )
  [ - abs 1 3 between? ] monotonic? ;

: safe? ( report -- ? )
  { [ slanted? ] [ gradual? ] } && ;

: part1 ( -- n )
  get-input [ safe? ] count ;

: fuzzy-reports ( report -- reports )
  dup length <iota> [ remove-nth-of ] with map ;

: tolerable? ( report -- ? )
  { [ safe? ] [ fuzzy-reports [ safe? ] any? ] } || ;

: part2 ( -- n )
  get-input [ tolerable? ] count ;
[–] [email protected] 2 points 3 weeks ago

Quite the interesting language choice. It's so clean. I love it!

[–] [email protected] 3 points 3 weeks ago

J

There is probably a way to write this more point-free. You can definitely see here the friction involved in the way J wants to regard lists as arrays: short rows of the input matrix are zero padded, so you have to snip off the padding before you process each row, and that means you can't lift some of the operations back up to the parent matrix because it will re-introduce the padding as it reshapes the result; this accounts for a lot of the "1 everywhere (you can interpret v"1 as "force the verb v to operate on rank 1 subarrays of the argument").

data_file_name =: '2.data'
data =: > 0 ". each cutopen toJ fread data_file_name

NB. {. take, i. index of; this removes trailing zeros
remove_padding =: {.~ i.&amp;0

NB. }. behead, }: curtail; this computes successive differences
diff =: }. - }:

NB. a b in_range y == a &lt;: y &lt;: b
in_range =: 4 : '(((0 { x) &amp; &lt;:) * (&lt;: &amp; (1 { x))) y'

NB. a row is safe if either all successive differences are in [1..3] or all in [_3.._1]
NB. +. or
ranges =: 2 2 $ 1 3 _3 _1
row_safe =: (+./"1) @: (*/"1) @: (ranges &amp; (in_range"1 _)) @: diff @: remove_padding

result1 =: +/ safe"1 data

NB. x delete y is y without the xth element
delete =: 4 : '(x {. y) , ((>: x) }. y)'"0 _
modified_row =: 3 : 'y , (i.#y) delete y'

modified_row_safe =: 3 : '+./"1 row_safe"1 modified_row"1 y'
result2 =: +/ modified_row_safe data
[–] [email protected] 3 points 3 weeks ago

Rust

use crate::utils::read_lines;

pub fn solution1() {
    let reports = get_reports();
    let safe_reports = reports
        .filter(|report| report.windows(3).all(window_is_valid))
        .count();

    println!("Number of safe reports = {safe_reports}");
}

pub fn solution2() {
    let reports = get_reports();
    let safe_reports = reports
        .filter(|report| {
            (0..report.len()).any(|i| {
                [&report[0..i], &report[i + 1..]]
                    .concat()
                    .windows(3)
                    .all(window_is_valid)
            })
        })
        .count();

    println!("Number of safe reports = {safe_reports}");
}

fn window_is_valid(window: &[usize]) -> bool {
    matches!(window[0].abs_diff(window[1]), 1..=3)
        && matches!(window[1].abs_diff(window[2]), 1..=3)
        && ((window[0] > window[1] && window[1] > window[2])
            || (window[0] < window[1] && window[1] < window[2]))
}

fn get_reports() -> impl Iterator<Item = Vec<usize>> {
    read_lines("src/day2/input.txt").map(|line| {
        line.split_ascii_whitespace()
            .map(|level| {
                level
                    .parse()
                    .expect("Reactor level is always valid integer")
            })
            .collect()
    })
}

Definitely trickier than yesterday's. I feel like the windows solution isn't the best, but it was what came to mind and ended up working for me.

[–] [email protected] 3 points 3 weeks ago (1 children)

TypeScript

Solution

import { AdventOfCodeSolutionFunction } from "./solutions";


/**
 * this function evaluates the 
 * @param levels a list to check
 * @returns -1 if there is no errors, or the index of where there's an unsafe event
 */
export function EvaluateLineSafe(levels: Array<number>) {
    // this loop is the checking every number in the line
    let isIncreasing: boolean | null = null;
    for (let levelIndex = 1; levelIndex < levels.length; levelIndex++) {
        const prevLevel = levels[levelIndex - 1]; // previous
        const level = levels[levelIndex]; // current
        const diff = level - prevLevel; // difference
        const absDiff = Math.abs(diff); // absolute difference

        // check if increasing too much or not at all
        if (absDiff == 0 || absDiff > 3)
            return levelIndex; // go to the next report

        // set increasing if needed
        if (isIncreasing === null) {
            isIncreasing = diff > 0;
            continue; // compare the next numbers
        }

        //  check if increasing then decreasing 
        if (!(isIncreasing && diff > 0 || !isIncreasing && diff < 0))
            return levelIndex; // go to the next report
    }

    return -1;
}


export const solution_2: AdventOfCodeSolutionFunction = (input) => {
    const reports = input.split("\n");

    let safe = 0;
    let safe_damp = 0;

    // this loop is for every line
    main: for (let i = 0; i < reports.length; i++) {
        const report = reports[i].trim();
        if (!report)
            continue; // report is empty

        const levels = report.split(" ").map((v) => Number(v));

        const evaluation = EvaluateLineSafe(levels);
        if(evaluation == -1) {
            safe++;
            continue;
        }
        
        // search around where it failed
        for (let offset = evaluation - 2; offset <= evaluation + 2; offset++) {
            // delete an evaluation in accordance to the offset
            let newLevels = [...levels];
            newLevels.splice(offset, 1);
            const newEval = EvaluateLineSafe(newLevels);
            if(newEval == -1) {
                safe_damp++;
                continue main;
            }
        }
    }

    return `Part 1: ${safe} Part 2: ${safe + safe_damp}`;
}

God, I really wish my solutions weren't so convoluted. Also, this is an O(N^3) solution....

[–] [email protected] 3 points 3 weeks ago (1 children)

I don't think your solution is O(N^3). Can you explain your reasoning?

[–] [email protected] 1 points 3 weeks ago (1 children)
[–] [email protected] 2 points 3 weeks ago (1 children)

It's not as simple as that. You can have 20 nested for loops with complexity of O(1) if all of them only ever finish one iteration.

Or you can have one for loop that iterates 2^N times.

[–] [email protected] 1 points 3 weeks ago (2 children)

What do you think my complexity is?

I think it could be maybe O(n^2) because the other for loop which tries elements around the first error will only execute a constant of 5 times in the worst case? I'm unsure.

[–] [email protected] 3 points 3 weeks ago

It's O(n).

If you look at each of the levels of all reports, you will access it a constant number of times: at most twice in each call to EvaluateLineSafe, and you will call EvaluateLineSafe at most six times for each report.

[–] [email protected] 2 points 3 weeks ago

It really depends on what your parameter n is. If the only relevant size is the number of records (let's say that is n), then this solution takes time in O(n), because it loops over records only once at a time. This ignores the length of records by considering it constant.

If we also consider the maximum length of records (let's call it m), then your solution, and most others I've seen in this thread, has a time complexity in O(n * m^2) for part 2.

[–] [email protected] 2 points 3 weeks ago

Lisp

Part 1

(defun p1-process-line (line)
  (mapcar #'parse-integer (str:words line)))

(defun line-direction-p (line)
  "make sure the line always goes in the same direction"
  (loop for x in line
        for y in (cdr line)
        count (> x y) into dec
        count (< x y) into inc
        when (and (> dec 0 ) (> inc 0)) return nil
        when (= x y) return nil
        finally (return t)))

(defun line-in-range-p (line)
  "makes sure the delta is within 3"
  (loop for x in line
        for y in (cdr line)
        for delta = (abs (- x y))
        when (or (> delta 3) )
          return nil 
        finally (return t)))

(defun test-line-p (line)
  (and (line-in-range-p line) (line-direction-p line)))

(defun run-p1 (file) 
  (let ((data (read-file file #'p1-process-line)))
    (apply #'+ (mapcar (lambda (line) (if (test-line-p line) 1 0)) data))))

Part 2

(defun test-line-p2 (line)
  (or (test-line-p (cdr line))
      (test-line-p (cdr (reverse line)))
  (loop for back on line
        collect (car back) into front
        when (test-line-p (concatenate 'list front (cddr back)))
          return t
        finally (return nil)
  )))

(defun run-p2 (file) 
  (let ((data (read-file file #'p1-process-line)))
    (loop for line in data
          count (test-line-p2 line))))

[–] [email protected] 2 points 3 weeks ago* (last edited 3 weeks ago)

I forgot that this started yesterday, so I'm already behind. I quite like my solution for part one, ~~but part two will have to wait~~ edit: part 2 was a lot simpler than I thought after a night's sleep.

Rust

use color_eyre::eyre;
use std::{fs, num, str::FromStr};

#[derive(Debug, PartialEq, Eq)]
struct Report(Vec<isize>);

impl FromStr for Report {
    type Err = num::ParseIntError;

    fn from_str(s: &str) -> Result<Self, Self::Err> {
        let v: Result<Vec<isize>, _> = s
            .split_whitespace()
            .map(|num| num.parse::<isize>())
            .collect();
        Ok(Report(v?))
    }
}

impl Report {
    fn is_safe(&self) -> bool {
        let ascending = self.0[1] > self.0[0];
        let (low, high) = if ascending { (1, 3) } else { (-3, -1) };
        self.0.windows(2).all(|w| {
            let a = w[0];
            let b = w[1];
            b >= a + low && b <= a + high
        })
    }

    fn is_dampsafe(&self) -> bool {
        if self.is_safe() {
            return true;
        }
        for i in 0..self.0.len() {
            let damped = {
                let mut v = self.0.clone();
                v.remove(i);
                Self(v)
            };
            if damped.is_safe() {
                return true;
            }
        }
        false
    }
}

fn main() -> eyre::Result<()> {
    color_eyre::install()?;

    let part1 = part1("d02/input.txt")?;
    let part2 = part2("d02/input.txt")?;
    println!("Part 1: {part1}\nPart 2: {part2}");
    Ok(())
}

fn part1(filepath: &str) -> eyre::Result<isize> {
    let mut num_safe = 0;
    for l in fs::read_to_string(filepath)?.lines() {
        if Report::from_str(l)?.is_safe() {
            num_safe += 1;
        }
    }
    Ok(num_safe)
}

fn part2(filepath: &str) -> eyre::Result<isize> {
    let mut num_safe = 0;
    for l in fs::read_to_string(filepath)?.lines() {
        if Report::from_str(l)?.is_dampsafe() {
            num_safe += 1;
        }
    }
    Ok(num_safe)
}

Tests

#[cfg(test)]
mod tests {
    use super::*;

    #[test]
    fn sample_part1() {
        assert_eq!(part1("test.txt").unwrap(), 2);
    }

    #[test]
    fn sample_part2() {
        assert_eq!(part2("test.txt").unwrap(), 4);
    }
}

[–] [email protected] 2 points 3 weeks ago

JavaScript

Also wrote a solution in JavaScript to play around with list comprehension. Wrote some utility functions for expressiveness (and lazy evaluation).

Code

const fs = require("fs");
const U = require("./util");

const isSafe = xs =>
    U.pairwise(xs).every(([a,b]) => a!==b && a-b > -4 && a-b < 4) &&
    new Set(U.pairwise(xs).map(([a,b]) => a < b)).size === 1;

const rows = fs
    .readFileSync(process.argv[2] || process.stdin.fd, "utf8")
    .split("\n")
    .filter(x => x != "")
    .map(x => x.split(/ +/).map(Number));

const p1 = U.countBy(rows, isSafe);
const p2 = U.countBy(rows, row =>
    isSafe(row) || U.someBy(U.indices(row),
        i => isSafe([...row.slice(0, i), ...row.slice(i+1)])));

console.log("02:", p1, p2);

https://github.com/sjmulder/aoc/blob/master/2024/js/day02.js

[–] [email protected] 2 points 3 weeks ago

This is my very naive rust solution, part 2 is mostly just an extra function, so they’re bother covered in this one.

AoC day 2

[–] [email protected] 2 points 3 weeks ago (1 children)

Haskell

Had some fun with arrows.

import Control.Arrow
import Control.Monad

main = getContents >>= print . (part1 &&& part2) . fmap (fmap read . words) . lines

part1 = length . filter isSafe
part2 = length . filter (any isSafe . removeOne)

isSafe = ap (zipWith (-)) tail >>> (all (between 1 3) &&& all (between (-3) (-1))) >>> uncurry (||)
 where
  between a b = (a <=) &&& (<= b) >>> uncurry (&&)

removeOne [] = []
removeOne (x : xs) = xs : fmap (x :) (removeOne xs)
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[–] [email protected] 2 points 3 weeks ago (1 children)

Nim

import strutils, times, sequtils, sugar

# check if level transition in record is safe
proc isSafe*(sign:bool, d:int): bool =
  sign == (d>0) and d.abs in 1..3;

#check if record is valid
proc validate*(record:seq[int]): bool =
  let sign = record[0] > record[1];
  return (0..record.len-2).allIt(isSafe(sign, record[it] - record[it+1]))

# check if record is valid as-is
# or if removing any item makes the record valid
proc validate2*(record:seq[int]): bool =
  return record.validate or (0..<record.len).anyIt(record.dup(delete(it)).validate)

proc solve*(input:string): array[2,int] =
  let lines = input.readFile.strip.splitLines;
  let records = lines.mapIt(it.splitWhitespace.map(parseInt));
  result[0] = records.countIt(it.validate);
  result[1] = records.countIt(it.validate2);

I got stuck on part 2 trying to check everything inside a single loop, which kept getting more ugly. So then I switched to just deleting one item at a time and re-checking the record.

Reworked it after first finding the solution to compress the code a bit, though the range iterators don't really help with readability.

I did learn about the sugar import, which I used to make the sequence duplication more compact: record.dup(delete(it).

[–] [email protected] 2 points 3 weeks ago* (last edited 3 weeks ago)

Cool to see another solution in Nim here =)

(0..<record.len).anyIt(record.dup(delete(it)).validate)

That's smart. I haven't thought of using iterators to loop over indexes (except in a for loop).

I got stuck on part 2 trying to check everything inside a single loop, which kept getting more ugly.

Yeah I've thought of simple ways to do this and found none. And looking at the input - it's too easy to bruteforce, especially in compiled lang like Nim.

[–] [email protected] 1 points 3 weeks ago (1 children)

Rust

Turned out alright, I am looking forward to seeing what 2d coordinate grid code I can cannibalize from last year's solutions πŸ˜„

Github link

[–] [email protected] 2 points 3 weeks ago (1 children)

I think that repo is private

[–] [email protected] 2 points 3 weeks ago

I realized after I posted πŸ˜… thanks for pointing it out! I will go make it public

[–] [email protected] 1 points 3 weeks ago (1 children)
def is_safe(report: list[int]) -> bool:
    global removed
    acceptable_range = [_ for _ in range(-3,4) if _ != 0]
    diffs = []
    if any([report.count(x) > 2 for x in report]):
        return False
    for i, num in enumerate(report[:-1]):
        cur = num
        next = report[i+1]
        difference = cur - next
        diffs.append(difference)
        if difference not in acceptable_range:
            return False
        if len(diffs) > 1:
            if diffs[-1] * diffs[-2] <= 0:
                return False
    return True

with open('input') as reports:
    list_of_reports = reports.readlines()[:-1]


count = 0

failed_first_pass = []
failed_twice = []

for reportsub in list_of_reports:
    levels = [int(l) for l in reportsub.split()]
    original = levels.copy()
    if is_safe(levels):
        safe = True
        count += 1
    else:
        failed_first_pass.append(levels)

for report in failed_first_pass:
    print(report)
    working_copy = report.copy()
    for i in range(len(report)):
        safe = False
        working_copy.pop(i)
        print("checking", working_copy)
        if is_safe(working_copy):
            count += 1
            safe = True
            break
        else:
            working_copy = report.copy()

print(count)
[–] [email protected] 1 points 3 weeks ago

this took me so fucking long and in the end i just went for brute force anyway. there are still remnants of some of previous, overly complicated, failed attempts, like the hideous global removed. In the end, I realized I was fucking up by using remove() instead of pop(), it was causing cases with duplicates where the removal of one would yield a safe result to count as unsafe.

[–] [email protected] 1 points 3 weeks ago

Kotlin:

import kotlin.math.abs
import kotlin.math.sign

data class Report(val levels: List<Int>) {
    fun isSafe(withProblemDampener: Boolean): Boolean {
        var orderSign = 0.0f  // - 1 is descending; +1 is ascending

        levels.zipWithNext().forEachIndexed { index, level ->
            val difference = (level.second - level.first).toFloat()
            if (orderSign == 0.0f) orderSign = sign(difference)
            if (sign(difference) != orderSign || abs(difference) !in 1.0..3.0) {
                // With problem dampener: Drop either element in the pair or the first element from the original list and check if the result is now safe.
                return if (withProblemDampener) {
                    Report(levels.drop(1)).isSafe(false) || Report(levels.withoutElementAt(index)).isSafe(false) || Report(levels.withoutElementAt(index + 1)).isSafe(false)
                }  else false
            }
        }

        return true
    }
}

fun main() {
    fun part1(input: List<String>): Int = input.map { Report(it.split(" ").map { it.toInt() }).isSafe(false) }.count { it }

    fun part2(input: List<String>): Int = input.map { Report(it.split(" ").map { it.toInt() }).isSafe(true) }.count { it }

    // Or read a large test input from the `src/Day01_test.txt` file:
    val testInput = readInput("Day02_test")
    check(part1(testInput) == 2)
    check(part2(testInput) == 4)

    // Read the input from the `src/Day01.txt` file.
    val input = readInput("Day02")
    part1(input).println()
    part2(input).println()
}

The Report#isSafe method essentially solves both parts.

I've had a bit of a trip up in part 2:

I initially only checked, if the report was safe, if either elements in the pair were to be removed. But in the edge case, that the first pair has different monotonic behaviour than the rest, the issue would only be detected by the second pair with indices (2, 3), whilst removing the first element in the list would yield a safe report.

[–] [email protected] 1 points 3 weeks ago

C#

using MathNet.Numerics.LinearAlgebra;
public class Day02 : Solver
{
  private ImmutableList<Vector<Double>> data;

  public void Presolve(string input)
  {
    data = input.Trim().Split("\n")
        .Select(
            line => Vector<Double>.Build.DenseOfEnumerable(line.Split(' ').Select(double.Parse))
        ).ToImmutableList();
  }

  private bool IsReportSafe(Vector<Double> report) {
    Vector<Double> delta = report.SubVector(1, report.Count - 1)
        .Subtract(report.SubVector(0, report.Count - 1));
    return (delta.ForAll(x => x > 0) || delta.ForAll(x => x < 0))
        && Vector<Double>.Abs(delta).Max() <= 3;
  }

  private bool IsDampenedReportSafe(Vector<Double> report) {
    for (Double i = 0; i < report.Count; ++i) {
      var dampened = Vector<Double>.Build.DenseOfEnumerable(
            report.EnumerateIndexed()
                .Where(item => item.Item1 != i)
                .Select(item => item.Item2));
      if (IsReportSafe(dampened)) return true;
    }
    return false;
  }

  public string SolveFirst() => data.Where(IsReportSafe).Count().ToString();

  public string SolveSecond() => data.Where(IsDampenedReportSafe).Count().ToString();
}
[–] [email protected] 1 points 2 weeks ago

Uiua

Took me a bit longer to get this one but still quite simple overall.
Spent quite some time on getting to know the try and assert operators better.

Run with example input here

# Get the indices matching the ascending/
# descending criteria
CheckAsc ← β‰‘Β°β–‘βš(⍣(⊸⍀.≍⍆.)⍣(⊸⍀.β‰β‡Œβ†.)0)
# Get the indices matching the distance criteria
CheckDist ← β‰‘Β°β–‘βš(⍣(⊸⍀.β‰ 1∈:0)0Γ—βŠ“β‰₯≀1,3⌡⧈-)
Split     ← βŠ™(β–½β‰ 1)β–½,,

PartOne ← (
  &rs ∞ &fo "input-2.txt"
  ⊜(β–‘βŠœβ‹•β‰ @ .)β‰ @\n.
  CheckAsc.
  β–½
  CheckDist
  ⧻⊚
)

PartTwo ← (
  &rs ∞ &fo "input-2.txt"
  ⊜(β–‘βŠœβ‹•β‰ @ .)β‰ @\n.
  CheckAsc.
  Split
  CheckDist.
  Split
  βŠ™(βŠ‚)
  ⧻
  :
  ⍚(≑(β–½:°⊟)⍜€⊞⊟:β‰ 1⊞=.⇑⧻.)
  ≑(⧻⊚CheckDistβ–½CheckAsc.Β°β–‘)
  +β§»β—΄βŠš
)

&p "Day 2:"
&pf "Part 1: "
&p PartOne
&pf "Part 2: "
&p PartTwo
[–] [email protected] 1 points 2 weeks ago

Elixir

defmodule AdventOfCode.Solution.Year2024.Day02 do
  use AdventOfCode.Solution.SharedParse

  @impl true
  def parse(input) do
    for line <- String.split(input, "\n", trim: true),
        do: String.split(line) |> Enum.map(&String.to_integer/1)
  end

  def part1(input) do
    Enum.count(input, &is_safe(&1, false))
  end

  def part2(input) do
    Enum.count(input, &(is_safe(&1, true) or is_safe(tl(&1), false)))
  end

  def is_safe([a, b, c | rest], can_fix) do
    cond do
      (b - a) * (c - b) > 0 and abs(b - a) in 1..3 and abs(c - b) in 1..3 ->
        is_safe([b, c | rest], can_fix)

      can_fix ->
        is_safe([a, c | rest], false) or is_safe([a, b | rest], false)

      true ->
        false
    end
  end

  def is_safe(_, _), do: true
end
[–] [email protected] 1 points 3 weeks ago

R (R-Wasm)

input = file('input2024day2.txt',open='r')
lines = readLines(input)
library(stringr)
safe = 0
safe2 = 0
for (ln in lines){
  vals = as.numeric(unlist(str_split(ln,' ')))
  diffs = diff(vals)
  cond1 = min(diffs) > 0 || max(diffs) < 0
  cond2 = max(abs(diffs)) < 4
  if (cond1 && cond2){
    safe = safe + 1
  }
  else { #Problem Dampener
    dampen = FALSE
    for (omit in -1:-length(vals)){
      diffs = diff(vals[omit])
      cond1 = min(diffs) > 0 || max(diffs) < 0
      cond2 = max(abs(diffs)) < 4
      if (cond1 && cond2){
        dampen = TRUE
      }
    }
    if (dampen){
      safe2 = safe2 + 1}
  }
}
print (safe) #Part 1
print (safe + safe2) #Part 2
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