375
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
this post was submitted on 18 Jul 2026
375 points (98.4% liked)
pics
29141 readers
1244 users here now
Rules:
1.. Please mark original photos with [OC] in the title if you're the photographer
2..Pictures containing a politician from any country or planet are prohibited, this is a community voted on rule.
3.. Image must be a photograph, no AI or digital art.
4.. No NSFW/Cosplay/Spam/Trolling images.
5.. Be civil. No racism or bigotry.
Photo of the Week Rule(s):
1.. On Fridays, the most upvoted original, marked [OC], photo posted between Friday and Thursday will be the next week's banner and featured photo.
2.. The weekly photos will be saved for an end of the year run off.
Instance-wide rules always apply. https://mastodon.world/about
founded 3 years ago
MODERATORS
If you enjoy it, it already has.
I get you but it was worth the money you spent ≠ it earned back the money you spent.
Okay but for real how long
have battery system and solar since jan 2023, still love it
Time, in hours (H), equals average solar kilowatt hours per month (K), multiplied by the price of one kilowatt hour (P), divided by the total cost (C) of all the purchased components.
H = (K * P) / C
I'm sure if you were patient and dedicated enough, you could approximate each of those numbers using the info OP has already posted and get a general idea (weeks, months, or years).
So you're dividing the average saving per month by the total cost and expecting to get hours?
If we generously estimate a very high 3000kWh/month generated and high $0.40/kWh price and it cost OP $9000, then you formula is (3000×0.40)/9000 = 0.133 hours.
Breaking even after less than 1 hour?!??! Extraordinary!
It's pretty easy to cry about bad math, but it's a lot harder to figure out the right math.
Don't worry, I'll try to do it for you again a second time.
Power consumption varies. Use the average monthly power draw from the solar array, let's assume for demonstration purposes 1,000 kWh/month.
Multiply that by the cost of 1 kWh from the power company, let's say 20 cents.
In one month, that means you saved $200.
Let's assume the solar equipment costs $1,000.
The answer is 5 months, or 5,000 kWh.
Sorry, I'll make sure the free work I do for you is better quality next time.
Bro. Don't act like this basic arithmetic and unit cancelation is hard. Not my fault you were so confidently incorrect.
Or I could read the comment where he said
Then do that instead of asking random people who aren't in any position to know.