this post was submitted on 25 Jun 2023
16 points (100.0% liked)

Jerboa

10299 readers
10 users here now

Jerboa is a native-android client for Lemmy, built using the native android framework, Jetpack Compose.

Warning: You can submit issues, but between Lemmy and lemmy-ui, I probably won't have too much time to work on them. Learn jetpack compose like I did if you want to help make this app better.

Built With

Features

Installation / Releases

Support / Donate

Jerboa is made by Lemmy's developers, and is free, open-source software, meaning no advertising, monetizing, or venture capital, ever. Your donations directly support full-time development of the project.

Crypto

Contact

founded 2 years ago
MODERATORS
 

Sorry if there's a megathread, didn't see anything pinned.

Anyway, please can someone tell me how I'm supposed to add specific instances? The search doesn't seem to show everything, or at least what I'm expecting to see. I'm signed up to lemm.ee. This jerboa place appeared in the search (before I joined) despite not being part of lemm.ee. However, I'm trying to find another page (https://lemmy.world/c/extrafabulous) but search doesn't find it and I don't know how to go directly there.

For the feedback, there's a function in the Joey app where you long-press a thumbail and it pops up the image in an enlarged preview that disappears as you let go. Can Jerboa do this? I kind got used to it as it meant not having to open images/videos in the browser.

Oh yeah and can we hide communities without blocking them? I don't really want to start blocking for the sake of it, but some communities appear in Local that aren't relevant to me.

you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 1 points 1 year ago

I'm not sure I got it right, but if you're not subscribed to a community you shouldn't see its posts once you're browsing with the "subscribed" option. If you want to browse using the "all" option and hide certain communities, then yes I think it would be a nice option to have.