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submitted 2 weeks ago* (last edited 2 weeks ago) by [email protected] to c/[email protected]

What I think in addition to what Atkinso writes: If you just strip arbitrary bytes that happen to be equal in value to the numeric value of ASCII control characters or whitespace, how can you be sure that you don't destroy valid non-whitespace unicode symbols?

You can't! This will work only of you have actually ASCII input.

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[-] [email protected] 6 points 2 weeks ago

In UTF8, all bytes that are not an ASCII character have the high bit set.

[-] [email protected] 1 points 2 weeks ago

This person Unicodes

[-] [email protected] -2 points 2 weeks ago

You are right with this. But still, in Rust, a vector of u8 is different from a sequence of unicode characters. This would not work in Python3 either, while it'd work in Python2.

[-] [email protected] 2 points 2 weeks ago* (last edited 2 weeks ago)

~~yeah it's incorrect bc it destroys multibyte characters, but~~ no idea what you're saying about u8 being a different type from unicode. the original code was reading bytes and converting them too? the typing isn't the issue, you can still store utf8 as a series of bytes

[-] [email protected] 1 points 2 weeks ago

it's incorrect bc it destroys multibyte characters

It doesn't. As the poster two levels up said, all bytes that don't represent an ASCII character have the high bit set, even the follow-up bytes in multibyte sequences. So the condition b >= 32 will match and preserve them.

[-] [email protected] 4 points 2 weeks ago

yeah fair enough. that wasn't really my point and I wasn't paying attention

[-] [email protected] 1 points 2 weeks ago

No, the filter is correct even for UTF-8. Any ASCII character is exactly unchanged in UTF-8 (part of the reason it is popular). Since this code only filters out ASCII characters it works fine with ASCII or UTF-8.

this post was submitted on 01 Jun 2025
24 points (90.0% liked)

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