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And 299999999 is divisible by 13 (lemmy.world)

submitted 3 days ago by [email protected] to c/[email protected]

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[–] [email protected] 8 points 3 days ago (2 children)

Well, on the side of easy ones there is "if the last digit is divisible by 2, whole number is divisible by 2". Also works for 5. And if you take last 2 digits, it works for 4. And the legendary "if it ends with 0, it's divisible by 10".

[–] [email protected] 9 points 3 days ago* (last edited 3 days ago) (1 children)

There’s also the classic “no three positive integers a, b, and c to satisfy a**n + b**n = c**n for values of n greater than 2“ trick but my proof is too large to fit in this comment.

[–] [email protected] 2 points 3 days ago

Fucking lol

[–] [email protected] 3 points 3 days ago (1 children)

Its never divisible by zero, and its always divisible by one

[–] [email protected] 3 points 3 days ago (1 children)

Never say never. 1/0 = 0

[–] [email protected] 1 points 3 days ago

Interesting read. Thank you.