▲ 154 ▼ In MCU Iron Man, the 3GW power output of the Arc reactor is channeled through 3 18AWG wires (thelemmy.club) submitted 1 day ago by sanitation@lemmy.today to c/shittymoviedetails@lemmy.world 37 comments fedilink hide all child comments
[–] Blue_Morpho@lemmy.world 7 points 1 day ago (1 child) Still gonna have heat that will melt the insulation and at extreme voltage it will arc through the insulation. permalink fedilink source parent hideshow 2 child comments replies: [–] smuuthbrane@sh.itjust.works 7 points 1 day ago (3 children) Heat is a function of current, not voltage. But yes, insulation would need to be extreme. permalink fedilink source parent hideshow 6 child comments replies: [–] Blue_Morpho@lemmy.world 2 points 19 hours ago* (1 child) Watts is volts x current. Ohms law means you can algebraically substitute V = I * R P = i^2 * R P = VI P = V^2 * R permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 3 points 13 hours ago Should be P = V^2 / R, but other than that, yes exactly. Everyone saying "it scales with voltage" or "it scales with resistance" are describing different sides of the same coin. At the end of the day, the thing we're talking about is just power, you can pick and choose whichever version of the power formula that you want. permalink fedilink source parent [–] dehyzer@piefed.social 1 point 1 day ago (2 children) Heat is actually a function of power, which is voltage times current. permalink fedilink source parent hideshow 4 child comments replies: [–] glibg10b@lemmy.zip 8 points 1 day ago* (1 child) Yes, but the power dissipated by a wire is, roughly speaking, a function of current, with the voltage across the wire depending on the current and the wire resistance (Ohm's law). For a wire, you use P = I^2^ R, and for a load, you use P = V^2^ / R. In other words, the current through a wire is dependent only on the load and its power supply, while the voltage across it depends on both the current and the size of the wire. Hence, it's cleaner to talk about the current This is why AWG charts always give a current rating, not a power rating: permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago You're right, current is a fine proxy for practical purposes like sizing wires and such. I was just being a bit pedantic in that heat fundamentally is power dissipation. permalink fedilink source parent [–] zeroblood@lemmy.ca 3 points 1 day ago (1 child) Joule's first law (also just Joule's law), states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current. Heat is a function of current, not total power. permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago See Blue_Morpho's comment above. The things you're describing as the product of resistance and the square of the current is power. Heat is literally power dissipation. Saying "heat is a function of power" is essentially a tautology. permalink fedilink source parent [+] plantfanatic@sh.itjust.works 1 point 1 day ago* [deleted] permalink fedilink source parent
[–] smuuthbrane@sh.itjust.works 7 points 1 day ago (3 children) Heat is a function of current, not voltage. But yes, insulation would need to be extreme. permalink fedilink source parent hideshow 6 child comments replies: [–] Blue_Morpho@lemmy.world 2 points 19 hours ago* (1 child) Watts is volts x current. Ohms law means you can algebraically substitute V = I * R P = i^2 * R P = VI P = V^2 * R permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 3 points 13 hours ago Should be P = V^2 / R, but other than that, yes exactly. Everyone saying "it scales with voltage" or "it scales with resistance" are describing different sides of the same coin. At the end of the day, the thing we're talking about is just power, you can pick and choose whichever version of the power formula that you want. permalink fedilink source parent [–] dehyzer@piefed.social 1 point 1 day ago (2 children) Heat is actually a function of power, which is voltage times current. permalink fedilink source parent hideshow 4 child comments replies: [–] glibg10b@lemmy.zip 8 points 1 day ago* (1 child) Yes, but the power dissipated by a wire is, roughly speaking, a function of current, with the voltage across the wire depending on the current and the wire resistance (Ohm's law). For a wire, you use P = I^2^ R, and for a load, you use P = V^2^ / R. In other words, the current through a wire is dependent only on the load and its power supply, while the voltage across it depends on both the current and the size of the wire. Hence, it's cleaner to talk about the current This is why AWG charts always give a current rating, not a power rating: permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago You're right, current is a fine proxy for practical purposes like sizing wires and such. I was just being a bit pedantic in that heat fundamentally is power dissipation. permalink fedilink source parent [–] zeroblood@lemmy.ca 3 points 1 day ago (1 child) Joule's first law (also just Joule's law), states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current. Heat is a function of current, not total power. permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago See Blue_Morpho's comment above. The things you're describing as the product of resistance and the square of the current is power. Heat is literally power dissipation. Saying "heat is a function of power" is essentially a tautology. permalink fedilink source parent [+] plantfanatic@sh.itjust.works 1 point 1 day ago* [deleted] permalink fedilink source parent
[–] Blue_Morpho@lemmy.world 2 points 19 hours ago* (1 child) Watts is volts x current. Ohms law means you can algebraically substitute V = I * R P = i^2 * R P = VI P = V^2 * R permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 3 points 13 hours ago Should be P = V^2 / R, but other than that, yes exactly. Everyone saying "it scales with voltage" or "it scales with resistance" are describing different sides of the same coin. At the end of the day, the thing we're talking about is just power, you can pick and choose whichever version of the power formula that you want. permalink fedilink source parent
[–] dehyzer@piefed.social 3 points 13 hours ago Should be P = V^2 / R, but other than that, yes exactly. Everyone saying "it scales with voltage" or "it scales with resistance" are describing different sides of the same coin. At the end of the day, the thing we're talking about is just power, you can pick and choose whichever version of the power formula that you want. permalink fedilink source parent
[–] dehyzer@piefed.social 1 point 1 day ago (2 children) Heat is actually a function of power, which is voltage times current. permalink fedilink source parent hideshow 4 child comments replies: [–] glibg10b@lemmy.zip 8 points 1 day ago* (1 child) Yes, but the power dissipated by a wire is, roughly speaking, a function of current, with the voltage across the wire depending on the current and the wire resistance (Ohm's law). For a wire, you use P = I^2^ R, and for a load, you use P = V^2^ / R. In other words, the current through a wire is dependent only on the load and its power supply, while the voltage across it depends on both the current and the size of the wire. Hence, it's cleaner to talk about the current This is why AWG charts always give a current rating, not a power rating: permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago You're right, current is a fine proxy for practical purposes like sizing wires and such. I was just being a bit pedantic in that heat fundamentally is power dissipation. permalink fedilink source parent [–] zeroblood@lemmy.ca 3 points 1 day ago (1 child) Joule's first law (also just Joule's law), states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current. Heat is a function of current, not total power. permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago See Blue_Morpho's comment above. The things you're describing as the product of resistance and the square of the current is power. Heat is literally power dissipation. Saying "heat is a function of power" is essentially a tautology. permalink fedilink source parent
[–] glibg10b@lemmy.zip 8 points 1 day ago* (1 child) Yes, but the power dissipated by a wire is, roughly speaking, a function of current, with the voltage across the wire depending on the current and the wire resistance (Ohm's law). For a wire, you use P = I^2^ R, and for a load, you use P = V^2^ / R. In other words, the current through a wire is dependent only on the load and its power supply, while the voltage across it depends on both the current and the size of the wire. Hence, it's cleaner to talk about the current This is why AWG charts always give a current rating, not a power rating: permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago You're right, current is a fine proxy for practical purposes like sizing wires and such. I was just being a bit pedantic in that heat fundamentally is power dissipation. permalink fedilink source parent
[–] dehyzer@piefed.social 1 point 13 hours ago You're right, current is a fine proxy for practical purposes like sizing wires and such. I was just being a bit pedantic in that heat fundamentally is power dissipation. permalink fedilink source parent
[–] zeroblood@lemmy.ca 3 points 1 day ago (1 child) Joule's first law (also just Joule's law), states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current. Heat is a function of current, not total power. permalink fedilink source parent hideshow 2 child comments replies: [–] dehyzer@piefed.social 1 point 13 hours ago See Blue_Morpho's comment above. The things you're describing as the product of resistance and the square of the current is power. Heat is literally power dissipation. Saying "heat is a function of power" is essentially a tautology. permalink fedilink source parent
[–] dehyzer@piefed.social 1 point 13 hours ago See Blue_Morpho's comment above. The things you're describing as the product of resistance and the square of the current is power. Heat is literally power dissipation. Saying "heat is a function of power" is essentially a tautology. permalink fedilink source parent