Yes, but the power dissipated by a wire is, roughly speaking, a function of current, with the voltage across the wire depending on the current and the wire resistance (Ohm's law). For a wire, you use P = I^2^ R, and for a load, you use P = V^2^ / R.

In other words, the current through a wire is dependent only on the load and its power supply, while the voltage across it depends on both the current and the size of the wire. Hence, it's cleaner to talk about the current

This is why AWG charts always give a current rating, not a power rating: