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submitted 1 week ago by [email protected] to c/[email protected]

I have a list of clothing items and a variable [gender] that contains value for example "♂️" male. Some items on the list of clothing also contain emojis ♀️ or ♂️ in them, something like "Batman suit♂️". I'm trying to exclude all items with ♀️ if "gender==♂️" and vice versa. I've tried to use clothingTop.selectAll.filter(newlist =>newlist.tags.includes([gender])), ald also match(/♀️/i), I'm not sure how to proceed.

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[-] [email protected] 1 points 1 week ago

On my end, there doesn't seem to be any problems? What method are you using, directly on the HTML, the $output method, or both? If both, then there might be a problem.

[-] [email protected] 1 points 1 week ago

How do I work with $output now in the list section to call an individual item from the list? I used to do it like this [clothingList[clothingGroup][clothingTop].joinItems(", ")] where clothingGroup is the html optgroup and clothingTop is the name of the item('this.value'). ${clothingTop[clothingGroup][clothingTop]} or clothingList[clothingGroup][clothingTop] returns undefined. Sorry for the noob question, as you can tell I'm new at this :-)

[-] [email protected] 2 points 1 week ago

I forgot to enclose the value=${this[a]} with quotations, so that is one problem. You can remove the value of the option if you are using the value to access back the list like so:

$output = [this.selectAll.map(a => a.getName).filter(a => gender.includes('♀️') ? !a.includes('♂️') : !a.includes('♀️')).map(a => `<option>${a}</option>`).join('')]

So that clothingTop will return the list name e.g. Dress♀️, then using it with [clothingList[clothingGroup][clothingTop]] should return the item below it i.e. evening dress with deep neckline.

Setting the value to this[a] would have the value of the option set directly to evening dress with deep neckline and not Dress♀️ so [clothingList[clothingGroup][clothingTop]] would not work, but you can access the value directly with clothingTop.

[-] [email protected] 1 points 1 week ago

Yeah that works, much appreciated! I noticed that the value was different from the name, it was lowerCase and no emoji that's why I couldn't call it.

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this post was submitted on 27 May 2025
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