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[–] 102 points 13 hours ago* (2 children)

On further inspection, it was found that the mathematician had assumed an ideal sphere of constant radius, while the real object was in fact oblate. The mathematician had neglected to take any measurements, leading to an incorrect value. The physicist's answer was correct, but only at sea level at nominal temperature.

The engineer is currently using calipers to measure the diameter of the object at many different angles in order to build a CAD model. He said we could expect results next year.

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  • [–] 48 points 12 hours ago (3 children)

    The physicist’s answer would be correct anywhere, no matter the temperature or density of the fluid.

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  • [–] 10 points 11 hours ago* (2 children)

    Assuming the time between submersion and observation is greater than zero, increasing temperatures above boiling would give increasing error.

    Conversely the physicist may get other error at/near freezing.

    And yet another option is the fluid being above the Ball's melting and/or boiling point, assuming changes in density with phase change.

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  • [–] 7 points 11 hours ago (1 child)

    All of which the physicist can trivially account for, control and variable test around, should the requested question be updated to require it.

    The requested question did not include "In all possible scenarios", thus determining the volume of the sphere via physics calculation at the most average of conditions, is the most correct valid solution, absent further requirement parameters.

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  • [–] 4 points 10 hours ago*

    You're right in terms of grading a student's homework or whatever.

    In research/publication/career these assumptions must be stated unless given.

    But I was responding to:

    The physicist’s answer would be correct anywhere, no matter the temperature or density of the fluid.

    Which includes non-standard conditions.

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  • [–] 8 points 12 hours ago*

    Interestingly, the physicist's answer would always be correct, but not always consistent.

    If the sphere is compressible, then air pressure will slightly affect its volume. And unless the thermal expansion rate of the sphere is zero, the amount of fluid displaced will also vary with temperature.

    However, even if the physicist gets different answers in different environments, it's always still a correct answer, because they correctly measured the volume of the sphere at that time.

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