Okay, lets redo the math with your new numbers.
- 11TWh (+6TWh) per day production.
- Average of 1/5 of maximum output (27MW * 24 = 648 MWh per day. 648 / 130 = factor of 5).
- 1 MW per 10 acres of solar power (It's 27MW on 120 acres at the DePue site)
- 270-675 million acres.
Now lets get all the units into average MW
- 700,000MW needed (17TWh per day = 0.7 TW average)
- 0.02MW per acre. (1MW / 10 / 5 = 0.02MW average)
That means 35 million acres. Now I'm going to post this immediately before double-checking my math previous maths, because this number should be about 10 times higher than my previous answer based on the numbers you've given me. Did I overestimate the land required in my first reply?
EDIT: Found my problem.
America consumes 25,000tWh of energy per year (about 7TWh per day, or 3TW)
7TWh per day is not 3TW, it's 0.3TW.