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No arguments here (sub.wetshaving.social)
submitted 1 year ago by to c/memes@lemmy.world
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[–] 1 point 1 year ago (5 children)

Since the straight lines are radii, they cut the circles at angle θ and 2π - θ, respectively. Adding those, you get 2π.

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  • [–] 1 point 1 year ago (4 children)

    Okay, but... Why? Is that a theorem that I don't remember from school?

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  • [–] 1 point 1 year ago* (3 children)

    Take this shape as an example. The "square" in question consists of AC, BD, the outer AB, and the inner CD.

    Point (5) means that, since the lines AC and BD are radii of the concentric circles, the arcs AB and CD should have the same inner angle. That's because the angle COD is equal to AOB.

    Since, the inner angle is the same, then the outer AOB should, by definition, be 2π - (the inner AOB), because that's how radiants work; a circle is 2π rads.

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  • [–] 1 point 1 year ago (1 child)

    Thank you! But why arc CD and arc AB length should add to 2 PI? Or why does the angle COD times two is 2PI if that's what you meant?

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  • [–] 1 point 1 year ago* (last edited 1 year ago)

    Point (5) is not about the arcs' lengths. It's about the angle they create with the center.

    Also, I never said that COD * 2 = 2π. I said (inner COD) + (outer COD) = 2π rads

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