nero comments on Call the Priest

[–] nero@lemmy.world 0 points 3 years ago (4 children)

You basically got it yeah. You can do x % 2 and check if that is 0, as % calculates the remainder (in python at least)

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[–] Guy_Fieris_Hair@lemmy.world 1 point 3 years ago* (3 children)

y = 1

while y ==1:

x = input("Enter Number")

if int(x) % 2 == 0:

print("EVEN")

else:

print("ODD")

I don't know why, but I opened up my IDLE for the first time in a year and did it.

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[–] MrMagnesium12@feddit.de 1 point 3 years ago

int val = 3;
bool is_odd = val & (decltype(val))0x01 == (decltype (val))1;

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[–] nero@lemmy.world 1 point 3 years ago (1 child)

Know you probably don’t care, but you can do a while loop using while True:

Which is the same as you using a statement which equals to true.

Thought i don’t think you need it for what you’re doing currently.

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[–] nero@lemmy.world 1 point 3 years ago

Unless you want it to keep asking the question of course**

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