▲ 830 ▼ I say double it. (feddit.ch) submitted 3 years ago by LemmyLaLibre@feddit.ch to c/memes@lemmy.ml 126 comments fedilink hide all child comments
[–] alerternate@lemmy.world 26 points 3 years ago (1 child) math checks out. log2(8 billion) ~= 32.9 permalink fedilink source parent hideshow 2 child comments replies: [–] ghariksforge@lemmy.world 9 points 3 years ago (2 children) It's a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula. permalink fedilink source parent hideshow 4 child comments replies: [–] RatMaster@sh.itjust.works 11 points 3 years ago (1 child) You could just move them over whenever someone decides to double it up. That way the person that was going to die alone is doomed to die anyway. 😂 permalink fedilink source parent hideshow 2 child comments replies: [–] Patawagon@lemmy.world 4 points 3 years ago (1 child) I wonder if we do stack it till every human is tied to the track whos at the lever? Does the train/AI decide? permalink fedilink source parent hideshow 2 child comments replies: [–] fneu@discuss.tchncs.de 3 points 3 years ago The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group… permalink fedilink source parent [–] sabazius@lemmy.world 10 points 3 years ago* (1 child) It'll just be one fewer junctions. 2^n is always one more than the sum of 2^1+...2^(n-1) permalink fedilink source parent hideshow 2 child comments replies: [–] Magikjak@lemmy.world 1 point 3 years ago I think you have to include 2^0 for that to be true? e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc. permalink fedilink source parent
[–] ghariksforge@lemmy.world 9 points 3 years ago (2 children) It's a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula. permalink fedilink source parent hideshow 4 child comments replies: [–] RatMaster@sh.itjust.works 11 points 3 years ago (1 child) You could just move them over whenever someone decides to double it up. That way the person that was going to die alone is doomed to die anyway. 😂 permalink fedilink source parent hideshow 2 child comments replies: [–] Patawagon@lemmy.world 4 points 3 years ago (1 child) I wonder if we do stack it till every human is tied to the track whos at the lever? Does the train/AI decide? permalink fedilink source parent hideshow 2 child comments replies: [–] fneu@discuss.tchncs.de 3 points 3 years ago The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group… permalink fedilink source parent [–] sabazius@lemmy.world 10 points 3 years ago* (1 child) It'll just be one fewer junctions. 2^n is always one more than the sum of 2^1+...2^(n-1) permalink fedilink source parent hideshow 2 child comments replies: [–] Magikjak@lemmy.world 1 point 3 years ago I think you have to include 2^0 for that to be true? e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc. permalink fedilink source parent
[–] RatMaster@sh.itjust.works 11 points 3 years ago (1 child) You could just move them over whenever someone decides to double it up. That way the person that was going to die alone is doomed to die anyway. 😂 permalink fedilink source parent hideshow 2 child comments replies: [–] Patawagon@lemmy.world 4 points 3 years ago (1 child) I wonder if we do stack it till every human is tied to the track whos at the lever? Does the train/AI decide? permalink fedilink source parent hideshow 2 child comments replies: [–] fneu@discuss.tchncs.de 3 points 3 years ago The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group… permalink fedilink source parent
[–] Patawagon@lemmy.world 4 points 3 years ago (1 child) I wonder if we do stack it till every human is tied to the track whos at the lever? Does the train/AI decide? permalink fedilink source parent hideshow 2 child comments replies: [–] fneu@discuss.tchncs.de 3 points 3 years ago The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group… permalink fedilink source parent
[–] fneu@discuss.tchncs.de 3 points 3 years ago The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group… permalink fedilink source parent
[–] sabazius@lemmy.world 10 points 3 years ago* (1 child) It'll just be one fewer junctions. 2^n is always one more than the sum of 2^1+...2^(n-1) permalink fedilink source parent hideshow 2 child comments replies: [–] Magikjak@lemmy.world 1 point 3 years ago I think you have to include 2^0 for that to be true? e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc. permalink fedilink source parent
[–] Magikjak@lemmy.world 1 point 3 years ago I think you have to include 2^0 for that to be true? e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc. permalink fedilink source parent
