Day 6: Trash Compactor

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FAQ

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[–] 6 points 10 months ago (4 children)

Uiua

I'm new to Uiua, so probably not the best way to express the solution!

ParseRows ← (
  βŠœβˆ˜βŠΈβ‰ @\n
  βœβ‡ŒΒ°βŠ‚ # Get the row of operations.
)
ParseOperations ← βŠœβŠ’βŠΈβ‰ @\s
SumCalculations ← (
  ≑(
    ⍣(β—‡/Γ—Β°@*
    | β—‡/+Β°@+
    )
  )
  /+
)

Part₁ ← (
  ParseRows
  βŠ“(ParseOperations
  | ⍉ ≑(βŠœβ‹•βŠΈβ‰ @\s) # Parse columns.
  )
  SumCalculations
)

Partβ‚‚ ← (
  ParseRows
  βŠ“(ParseOperations
  | ⊜(░≑(β‹•β–½βŠΈβ‰ @\s)) ≑/β†₯βŠΈβ‰ @\s⍉ # Parse numbers.
  )
  SumCalculations
)

&fras "6.txt"
βŠƒPart₁ Partβ‚‚
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  • hideshow 4 child comments
  • [–] 4 points 10 months ago

    nushell

    I was afk when the puzzle went up so I had another go at doing it on my phone in Turmux with my shell's scripting language. It's quite nice how your shell is also a REPL so you can build up the answer in pieces, although I wrote a file for the second part.

    Phone screenshot of my solution being developed

    open input.txt | str replace --all --regex ' +' ' ' |
            lines | each { $in | str trim } | to text |
            from csv --noheaders --separator ' ' |
            reverse | transpose --ignore-titles |
            each --flatten {
                    |list| transpose | skip 1 | if $list.column0 == '+' { math sum } else { math product }
            } |
            math sum
    

    Part 2

    let input = open input.txt | lines | each { $in | split chars }
    let last_row = ($input | length) - 1
    let last_col = ($input | first | length) - 1
    
    mut op = ' '
    mut numbers = []
    mut grand_tot = 0
    for x in $last_col..0 {
      if $op == '=' {
        $op = ' '
        continue
      }
      let n = 0..($last_row - 1) | each { |y| $input | get $y | get $x } | str join | into int
      $numbers = ($numbers | append $n)
    
      $op = $input | get $last_row | get $x
      if $op != ' ' {
        $grand_tot += $numbers | if $op == '+' { math sum } else {math product }
        $numbers = []
        $op = '='
      }
    }
    $grand_tot
    
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  • [–] 4 points 10 months ago

    Uiua

    This was fun :D

    I had a fun experience just throwing the strings with both numbers and spaces at the parse function. In the online pad, everything worked out fine but running the same code on my input locally gave me a "invalid float literal" error.
    I thought I'd missed some edge case in the real input again, like is often the case.
    Turns out that the Uiua version I used locally had a bug that's fixed in the latest build. For once it wasn't directly my fault ^^

    Run with example input

    Code

    $ 123 328  51 64 
    $  45 64  387 23 
    $   6 98  215 314
    $ *   +   *   +  
    
    # &fras "input-6.txt" β—Œ
    
    Calc ← (
      β†˜β‚‚βŠ›βŠ‚"+*"/β—‡βŠ‚
      ≑◇⨬(/+|/Γ—)
      /+
    )
    
    P₁ ← (
      ⊜(βŠœβ–‘βŠΈβ‰ @ )βŠΈβ‰ @\n
      βŠƒβŠ£β†˜β‚‹β‚
      βŠ™(⍉≑₀◇⋕)
      Calc
    )
    
    Pβ‚‚ ← (
      βŠœβˆ˜βŠΈβ‰ @\n
      ⟜⧻
      βŠ“β‰(Λœβ†―@ )
      ⊜(βŠ™(░≑⋕)βœβ‰(βŠƒ(⊒⊣)β†˜β‚‹β‚))Β¬β€šβ‰‘βŒŸβ‰
      Calc
    )
    
    1_2 [βŠƒP₁Pβ‚‚]
    ≑(&p &pf $"Part _: ")
    
    

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  • [–] 3 points 10 months ago

    Haskell

    import Control.Arrow
    import Data.Char
    import Data.List
    import Text.ParserCombinators.ReadP
    
    op "*" = product
    op "+" = sum
    
    part1 s = sum $ zipWith ($) (op <$> a) (transpose $ fmap read <$> as)
      where
        (a : as) = reverse . fmap words . lines $ s
    
    parseGroups = fst . last . readP_to_S (sepBy (endBy int eol) eol) . filter (/= ' ')
      where
        eol = char '\n'
        int = read <$> munch1 isDigit :: ReadP Int
    
    part2 s = sum $ zipWith ($) (op <$> words a) (parseGroups . unlines $ reverse <$> transpose as)
      where
        (a : as) = reverse $ lines s
    
    main = getContents >>= print . (part1 &&& part2)
    
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  • [–] 3 points 10 months ago (5 children)

    Haskell

    There's probably a really clever way of abstracting just the difference between the two layouts.

    import Data.Char (isSpace)  
    import Data.List (transpose)  
    import Data.List.Split (splitWhen)  
    
    op '+' = sum  
    op '*' = product  
    
    part1 =  
      sum  
        . map ((op . head . last) <*> (map read . init))  
        . (transpose . map words . lines)  
    
    part2 =  
      sum  
        . map ((op . last . last) <*> map (read . init))  
        . (splitWhen (all isSpace) . reverse . transpose . lines)  
    
    main = do  
      input <- readFile "input06"  
      print $ part1 input  
      print $ part2 input  
    
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  • hideshow 5 child comments
  • [–] 3 points 10 months ago (2 children)

    Your code really reads like your explaining the solution out loud. That's so elegant!

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  • hideshow 2 child comments
  • [–] 2 points 9 months ago

    Managed to keep it compact, but boy, do I hate cephalopod math >_<

    Python

    from csv import reader
    from functools import reduce
    from itertools import pairwise
    from operator import mul
    from pathlib import Path
    from typing import Any, List, Sequence
    
    
    def _calc(values: List[str]) -> int:
        match values[-1]:
            case "+":
                return sum(map(int, values[:-1]))
            case "*":
                return reduce(mul, map(int, values[:-1]))
            case _:
                return 0
    
    
    def _transpose(values: Sequence[Sequence[Any]]) -> List[List[Any]]:
        return [[values[row][col] for row in range(len(values))] for col in range(len(values[0]))]
    
    
    def part_one(input: str) -> int:
        def _parse_input(input: str) -> List[List[str]]:
            return _transpose(list(map(lambda r: list(filter(None, r)), reader(input.splitlines(), delimiter=" "))))
    
        return sum(map(_calc, _parse_input(input)))
    
    
    def part_two(input: str) -> int:
        def _parse_input(input: str) -> List[List[str]]:
            data = list(input.splitlines())
            columns = [t[0] for t in filter(lambda t: t[1] != " ", enumerate(data[-1]))] + [len(data[0])]
            numbers = [[line[a:b] for line in data[:-1]] for a, b in pairwise(columns)]
            numbers = [list(filter(None, ["".join(num).strip() for num in column])) for column in map(_transpose, numbers)]
            return list(map(lambda t: t[0] + [t[1]], zip(numbers, list(filter(None, data[-1].split(" "))))))
    
        return sum(map(_calc, _parse_input(input)))
    
    
    if __name__ == "__main__":
        input = Path("_2025/_6/input").read_text("utf-8")
        print(part_one(input))
        print(part_two(input))
    
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  • [–] 2 points 10 months ago*

    Python

    For part1, regex is king. Thought about rotating the grid for part2, but going column by column is simple enough.

    view code

    import re
    from operator import add, mul
    
    def part1(data: str):
        # split into row, but do not split into cells yet
        rows = data.splitlines()
        m = len(rows)   # number of rows
    
        # initialize the result and operator arrays
        # the operators array will store the operator function for each column block
        # the result array will store the initial value for each column block
        operators = []
        res = []
        # using regex to skip variable number of spaces
        for symbol in re.findall(r'\S', rows[-1]):
            if symbol == '+':
                operators.append(add)
                res.append(0)
            elif symbol == '*':
                operators.append(mul)
                res.append(1)
    
        n = len(res)    # number of columns
        # iterate through each row, except the last one
        for i in range(m-1):
            # use regex to find all numbers in the row
            for j, num in enumerate(map(int, re.findall(r'\d+', rows[i]))):
                # apply the operator to update the result for the appropriate column
                res[j] = operators[j](res[j], num)
    
        return sum(res)
    
    def part2(data: str):
        # completely split into grid
        grid = [list(line) for line in data.splitlines()]
        m, n = len(grid), len(grid[0])
        
        res = 0
        
        curr = None     # current value of the block
        op = None       # operator for the block
        for j in range(n):
            if curr is None:
                # we just started a new block
                # update the current value and operator based on the symbol
                symbol = grid[-1][j]
                curr = 0 if symbol == '+' else 1
                op = add if symbol == '+' else mul
            
            # read the number from the column
            num = 0
            for i in range(m-1):
                if grid[i][j] != ' ':
                    num = num * 10 + int(grid[i][j])
            # if there is no number, we are at the end of a block
            if num == 0:
                # add the block value to the result
                #   and reset the current value and operator
                res += curr
                curr = None
                op = None
                continue
            
            # otherwise, update the current value using the operator
            curr = op(curr, num)
        # finally, don't forget to add the last block value that's being tracked
        res += curr
    
        return res
    
    sample = """123 328  51 64 
     45 64  387 23 
      6 98  215 314
    *   +   *   +  """
    assert part1(sample) == 4277556
    assert part2(sample) == 3263827
    

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  • [–] 2 points 10 months ago

    Go

    Damn, I actually reeaally enjoy this one! I didn't expect the twist of part 2, but somehow it wasn't that hard to manage.

    Here is my modern solution:

    day06.go

    package main
    
    import (
    	"aoc/utils"
    	"fmt"
    	"regexp"
    	"slices"
    	"strconv"
    	"strings"
    )
    
    type operation int
    
    func (o operation) compute(values []int) int {
    	switch o {
    	case add:
    		sum := 0
    		for _, val := range values {
    			sum += val
    		}
    		return sum
    	case mul:
    		product := 1
    		for _, val := range values {
    			product *= val
    		}
    		return product
    	}
    
    	return 0
    }
    
    const (
    	add operation = iota
    	mul
    )
    
    var allOperationSymbols = []string{"+", "*"}
    
    func operationFromSymbol(sym string) operation {
    	switch sym {
    	case "+":
    		return add
    	case "*":
    		return mul
    	default:
    		panic(fmt.Sprintf("wtf is a %s?", sym))
    	}
    }
    
    type problems struct {
    	values     [][]int
    	operations []operation
    }
    
    func (p *problems) feed(column string) {
    	last := string(column[len(column)-1])
    	done := false
    
    	if slices.Contains(allOperationSymbols, last) {
    		p.operations = append(p.operations, operationFromSymbol(last))
    		column = column[:len(column)-1]
    		done = true
    	}
    
    	val, _ := strconv.Atoi(strings.TrimSpace(column))
    	idx := len(p.values) - 1
    	p.values[idx] = append(p.values[idx], val)
    
    	if done {
    		p.values = append(p.values, []int{})
    	}
    }
    
    func (p *problems) addLine(line string) (done bool) {
    	parts := strings.Split(line, " ")
    	parts = slices.DeleteFunc(parts, func(elem string) bool {
    		return elem == ""
    	})
    
    	if slices.Contains(allOperationSymbols, parts[0]) {
    		p.operations = make([]operation, len(parts))
    		for idx, sym := range parts {
    			p.operations[idx] = operationFromSymbol(sym)
    		}
    		done = true
    	} else {
    		if len(p.values) == 0 {
    			lenparts := len(parts)
    			p.values = make([][]int, lenparts)
    			for idx := range lenparts {
    				p.values[idx] = []int{}
    			}
    		}
    
    		for idx, part := range parts {
    			num, _ := strconv.Atoi(part)
    			p.values[idx] = append(p.values[idx], num)
    		}
    		done = false
    	}
    
    	return done
    }
    
    func (p problems) solve() []int {
    	solutions := make([]int, len(p.values))
    
    	for idx, values := range p.values {
    		op := p.operations[idx]
    		solutions[idx] = op.compute(values)
    	}
    
    	return solutions
    }
    
    func stepOne(input chan string) (int, error) {
    	modernProblems := problems{}
    	for line := range input {
    		done := modernProblems.addLine(line)
    		if done {
    			break
    		}
    	}
    
    	modernSolutions := modernProblems.solve()
    	sum := 0
    	for _, solution := range modernSolutions {
    		sum += solution
    	}
    
    	return sum, nil
    }
    
    func transposeInputChan(input chan string) []string {
    	lines := [][]rune{}
    	for line := range input {
    		lines = append(lines, []rune(line))
    	}
    
    	linecount := len(lines)
    	columncount := len(lines[0])
    	transposed := make([][]rune, columncount)
    
    	for idx := range transposed {
    		transposed[idx] = make([]rune, linecount)
    	}
    
    	for row, line := range lines {
    		for col, char := range line {
    			transposed[col][row] = char
    		}
    	}
    
    	columns := make([]string, len(transposed))
    	for idx, col := range transposed {
    		columns[idx] = string(col)
    	}
    
    	return columns
    }
    
    func stepTwo(input chan string) (int, error) {
    	transposedInput := transposeInputChan(input)
    	slices.Reverse(transposedInput)
    
    	// problem-set with one empty problem.
    	modernProblems := problems{
    		values: [][]int{[]int{}},
    	}
    
    	for _, column := range transposedInput {
    		if matched, _ := regexp.MatchString("^\\s*$", column); matched {
    			continue
    		}
    
    		modernProblems.feed(column)
    	}
    
    	// Remove last useless empty problem.
    	modernProblems.values = modernProblems.values[:len(modernProblems.values)-1]
    
    	modernSolutions := modernProblems.solve()
    	sum := 0
    	for _, solution := range modernSolutions {
    		sum += solution
    	}
    
    	return sum, nil
    }
    
    func main() {
    	inputFile := utils.FilePath("day06.txt")
    	utils.RunStep(utils.ONE, inputFile, stepOne)
    	utils.RunStep(utils.TWO, inputFile, stepTwo)
    }
    

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  • [–] [S] 2 points 10 months ago

    Excel

    Pt1 - Its a solution, but the column width on Numbers prevents a full solution

    https://docs.google.com/spreadsheets/d/e/2PACX-1vTzFApVAk9k5Q4EQhozST1HftYLgVzApgxjQx7MAl5AAE5eWEvrQnDQWmdj7J2Hyw/pub?output=ods

    If I get p2 working, I'll post a new link. Dont think i will have much luck though.

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  • [–] 2 points 10 months ago
    [–] 2 points 10 months ago

    C

    Well so much for reading a grid of ints in part 1! For part 2, initially I reworked the parsing to read into a big buffer, but then thought it would be fun to try and use memory-mapped I/O as not to use any more memory than strictly necessary for the final version:

    Code

    #include <stdio.h>
    #include <stdlib.h>
    #include <inttypes.h>
    #include <ctype.h>
    #include <assert.h>
    #include <sys/mman.h>
    #include <unistd.h>
    #include <err.h>
    
    #define GH	5
    
    int
    main()
    {
    	char *data, *g[GH], *p;
    	uint64_t p1=0,p2=0, acc;
    	int len, h=0, i, x,y, val;
    	char op;
    
    	if ((len = (int)lseek(0, 0, SEEK_END)) == -1)
    		err(1, "<stdin>");
    	if (!(data = mmap(NULL, len, PROT_READ, MAP_SHARED, 0, 0)))
    		err(1, "<stdin>");
    	for (i=0; i<len; i++)
    		if (!i || data[i-1]=='\n') {
    			assert(h < GH);
    			g[h++] = data+i;
    		}
    
    	for (x=0; g[h-1]+x < data+len; x++) {
    		if ((op = g[h-1][x]) != '+' && op != '*')
    			continue;
    
    		for (acc = op=='*', y=0; y<h-1; y++) {
    			val = atoi(&g[y][x]);
    			acc = op=='+' ? acc+val : acc*val;
    		}
    
    		p1 += acc;
    
    		for (acc = op=='*', i=0; ; i++) {
    			for (val=0, y=0; y<h-1; y++) {
    				p = &g[y][x+i];
    				if (p < g[y+1] && isdigit(*p))
    					val = val*10 + *p-'0';
    			}
    			if (!val)
    				break;
    			acc = op=='+' ? acc+val : acc*val;
    		}
    
    		p2 += acc;
    	}
    
    	printf("06: %"PRIu64" %"PRIu64"\n", p1, p2);
    }
    

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  • [–] 2 points 10 months ago*

    Ironically for Lisp, a good chunk of the work here is type conversion, because strings, vectors, multidimensional arrays, characters, and numbers don't have implicit conversions between them; you have to specify what you want explicitly. I also found it easier to manually transpose the character array for part 2 rather than traverse in column-major order, because that makes the relationship between input and output data structure more transparent.

    (ql:quickload :str)
    (ql:quickload :array-operations)
    
    (defun parse-line-1 (line)
      (let ((broken-line (str:split " " (str:collapse-whitespaces (str:trim line)))))
        (mapcar #'(lambda (s)
                    (cond ((equal s "+") #'+)
                          ((equal s "*") #'*)
                          (t (parse-integer s))))
                broken-line)))
    
    (defun read-inputs-1 (filename)
      (let* ((input-lines (uiop:read-file-lines filename)))
        (mapcar #'parse-line-1 input-lines)))
    
    (defun main-1 (filename)
      (let* ((problems (read-inputs-1 filename))
             (arguments (apply #'mapcar #'list (butlast problems))))
        (reduce #'+ (mapcar #'apply (car (last problems)) arguments))))
    
    (defun parse-operands-2 (lines)
      (let* ((initial-rows (length lines))
             (initial-cols (length (car lines)))
             (flat-chars (make-array (list (* initial-rows initial-cols))
                                     :initial-contents (apply #'concatenate 'string lines)))
             (box-chars (make-array (list initial-rows initial-cols) :displaced-to flat-chars))
             (transposed-chars (aops:each-index (i j) (aref box-chars j i))))
        (loop for cv across (aops:split transposed-chars 1)
              for s = (str:trim (coerce cv 'string))
              collect (if (zerop (length s)) nil (parse-integer s)))))
    
    (defun list-split (xs sep &optional (predicate #'equal))
      (let ((current nil)
            (result nil))
        (loop for x in xs
              do (if (funcall predicate x sep)
                     (progn
                       (setf result (cons (reverse current) result))
                       (setf current nil))
                     (setf current (cons x current)))
              finally (setf result (cons (reverse current) result)))
        (reverse result)))
    
    (defun main-2 (filename)
      (let* ((lines (uiop:read-file-lines filename))
             (operators (parse-line-1 (car (last lines))))
             (operands (parse-operands-2 (butlast lines))))
        (loop for rator in operators
              for rands in (list-split operands nil)
              sum (apply rator rands))))
    
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  • [–] 2 points 10 months ago

    Ruby

    I decided to rotate the entire input character-by-character, then parse the numbers (see the full source here)

    grid = input.lines.map(&:chomp).map {|l| l.each_char.map.to_a }.to_a
    transposed = Array.new(grid[0].length) { Array.new(grid.length) }
    
    grid.each_with_index do |row, y|
      row.each_with_index do |col, x|
        transposed[x][y] = col
      end
    end
    
    vals = []
    ops = []
    temp_vals = []
    
    transposed.each do |row|
      l = row.join("").strip
      temp_vals << l.scan(/\d+/).map(&:to_i).to_a[0]
      /[+*]/.match(l) { |m| ops << m.to_s.to_sym }
    
      if l == ""
        vals << temp_vals.compact
        temp_vals = []
      end
    end
    
    vals << temp_vals.compact unless temp_vals.empty?
    
    vals.each_with_index.sum do |v, i|
      v.inject(ops[i])
    end
    
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  • [–] 2 points 10 months ago*

    Kotlin

    More grid stuff and two-dimensional problem solving, I like it!
    The first part just requires extracting the numbers and operators, transposing the grid and summing/multiplying the numbers.
    The second part is also not too hard. I just search for the numbers in the transposed grid, making sure to leave out the last column. That one might contain an operator ("+" or "*"). Remember it for later. If the entire row is made of spaces, we have finished parsing a math problem. Just remember to account for the last one! πŸ˜…
    As with part one, just reduce the found problems and we're done!

    This solution requires the trailing spaces to be present in the input files. I had to disable an option in my IDE to prevent it from breaking my nice solution.

    Code on Github

    Code

    class Day06 : AOCSolution {
        override val year = 2025
        override val day = 6
    
        override fun part1(inputFile: String): String {
            val worksheet = readResourceLines(inputFile)
            // Arrange the problem in a grid and transpose it, so that the operation is the last element of each row
            val problems = worksheet.map { line -> line.trim().split(spaceSplitRegex) }.toGrid().transposed()
    
            val grandTotal = problems.rows().sumOf { line ->
                // Map the all but the last element to a number
                val numbers = line.mapToLongArray(0, line.lastIndex - 1, String::toLong)
                // Extract the operation
                val operation = line.last()[0]
    
                // Call the correct reduction
                // The "else" branch is needed for the compiler
                when (operation) {
                    ADD -> numbers.sum()
                    MULTIPLY -> numbers.reduce { acc, value -> acc * value }
                    else -> 0
                }
            }
            return grandTotal.toString()
        }
    
        override fun part2(inputFile: String): String {
            val worksheet = readResourceLines(inputFile)
    
            // In this part the problem is more complicated and dependent on the individual characters.
            val charGrid = worksheet.map(CharSequence::toList).toCharGrid().transposed()
    
            val numbers = mutableListOf<Long>()
            val sb = StringBuilder(charGrid.width)
    
            val problems = buildList {
                // Begin with an empty operation
                // Assume the operation will be set to a valid value
                var operation = SPACE
                for (y in 0 until charGrid.height) {
                    // Extract each row (transposed column)
                    sb.clear().append(charGrid[y])
                    // Find the bounds of the number
                    val numberOffset = sb.indexNotOf(SPACE)
    
                    if (numberOffset != -1) {
                        // A number was found, parse it and add it to the list.
                        val endIndex = sb.indexOfAny(STOP_CHARACTERS, numberOffset + 1)
                        val number = java.lang.Long.parseLong(sb, numberOffset, endIndex, 10)
                        numbers.add(number)
    
                        // Check whether there is an operation in the last column.
                        // IF so, that's the next relevant operation
                        val lastColumn = sb[sb.lastIndex]
                        if (lastColumn != SPACE) {
                            operation = lastColumn
                        }
                    } else {
                        // No number was found, that's the separator for two calculations.
                        // Finalize the collection and clear the numbers.
                        // `toLongArray` creates a neat copy of the Longs in the list.
                        add(Problem(operation, numbers.toLongArray()))
                        numbers.clear()
                    }
                }
                // Add the last remaining problem to the list
                add(Problem(operation, numbers.toLongArray()))
            }
    
            // Reduce all problems to their solutions and sum them up.
            val grandTotal = problems.sumOf { problem ->
                when (problem.operation) {
                    ADD -> problem.numbers.sum()
                    MULTIPLY -> problem.numbers.reduce { acc, value -> acc * value }
                    else -> 0
                }
            }
    
            return grandTotal.toString()
        }
    
        private companion object {
            private const val ADD = '+'
            private const val MULTIPLY = '*'
            private const val SPACE = ' '
            private val STOP_CHARACTERS = charArrayOf(SPACE, ADD, MULTIPLY)
    
            @JvmRecord
            @Suppress("ArrayInDataClass")
            private data class Problem(val operation: Char, val numbers: LongArray)
        }
    

  • source
  • [–] 2 points 10 months ago

    (Browser-based) Javascript

    I got lazy and lucky writing the first part; hard-coded the number of lines / operands and it worked on the first try! I didn't factor in the final block not being padded by spaces on both sides for part 2, and so needed to test on the example code – which has 3 lines of operands instead of the problem input's 4 lines, so I had to properly solve the problem across all possible amounts of lines of input 😩.

    I am very jealous of all y'all who have a transpose function available in your language of choice.

    Code

    function part1(inputText) {
      const [firstArgs, secondArgs, thirdArgs, fourthArgs, operators] = inputText.trim().split('\n').map(line => line.trim().split(/\s+/));
      let totalSum = 0;
      for (let i = 0; i < firstArgs.length; i++) {
        if (operators[i] === '+') {
          totalSum += Number.parseInt(firstArgs[i], 10) + Number.parseInt(secondArgs[i], 10) + Number.parseInt(thirdArgs[i], 10) + Number.parseInt(fourthArgs[i], 10);
        } else if (operators[i] === '*') {
          totalSum += Number.parseInt(firstArgs[i], 10) * Number.parseInt(secondArgs[i], 10) * Number.parseInt(thirdArgs[i], 10) * Number.parseInt(fourthArgs[i], 10);
        }
      }
      return totalSum
    }
    
    {
      const start = performance.now();
      const result = part1(document.body.textContent);
      const end = performance.now();
      console.info({
        day: 6,
        part: 1,
        time: end - start,
        result
      })
    }
    
    function part2(inputText) {
      const lines = inputText.trimEnd().split('\n');
      const interBlockIndices = [];
      for (let i = 0; i < lines[0].length; i++) {
        let allEmpty = true;
        for (let j = 0; j < lines.length; j++) {
          if (lines[j][i] !== ' ') {
            allEmpty = false;
            break;
          }
        }
        if (allEmpty) {
          interBlockIndices.push(i);
        }
      }
      interBlockIndices.push(lines[0].length);
    
      let totalSum = 0;
      let blockStart = 0;
      for (const interBlockIndex of interBlockIndices) {
        // compute calculation of block [blockStart, interBlockIndex - 1]
        const operands = [];
        for (let i = interBlockIndex - 1; i >= blockStart; i--) {
          // parse operands
          let operand = 0;
          for (let j = 0; j < lines.length - 1; j++) {
            if (lines[j][i] !== ' ') {
              operand *= 10;
              operand += Number.parseInt(lines[j][i], 10);
            }
          }
          operands.push(operand)
        }
        if (lines.at(-1)[blockStart] === '+') {
          totalSum += operands.reduce((accu, next) => accu + next, 0);
        } else if (lines.at(-1)[blockStart] === '*') {
          totalSum += operands.reduce((accu, next) => accu * next, 1);
        }
        //  console.debug({ totalSum, operands, blockStart, interBlockIndex });
        blockStart = interBlockIndex + 1;
      }
      return totalSum;
    }
    
    {
      const example = `123 328  51 64 
     45 64  387 23 
      6 98  215 314
    *   +   *   +  
    `;
      const start = performance.now();
      const result = part2(document.body.textContent);
      //   const result = part2(example);
      const end = performance.now();
      console.info({
        day: 6,
        part: 2,
        time: end - start,
        result
      })
    }
    
    

  • source
  • [–] [S] 2 points 10 months ago* (last edited 10 months ago) (2 children)

    Rust

    Pt1 easy, pt2 cry

    edit: Updated with more iterring :)

    view code

        #[test]
        fn test_y2025_day6_part1() {
            let input = include_str!("../../input/2025/day_6.txt");
            let lines = input.lines().collect::<Vec<&str>>();
            let nr = lines[0..4]
                .iter()
                .map(|l| {
                    l.split_whitespace()
                        .map(|s| s.parse::<usize>().unwrap())
                        .collect::<Vec<usize>>()
                })
                .collect::<Vec<Vec<usize>>>();
            let operations = lines[4].split_whitespace().collect::<Vec<&str>>();
    
            let total = operations
                .iter()
                .enumerate()
                .map(|(i, op)| match *op {
                    "*" => [0, 1, 2, 3].iter().map(|j| nr[*j][i]).product::<usize>(),
                    "+" => [0, 1, 2, 3].iter().map(|j| nr[*j][i]).sum::<usize>(),
                    _ => panic!("Unknown operation {}", op),
                })
                .sum::<usize>();
            assert_eq!(4412382293768, total);
            println!("Total: {}", total);
        }
    
        #[test]
        fn test_y2025_day6_part2() {
            let input = std::fs::read_to_string("input/2025/day_6.txt").unwrap();
            let lines = input
                .lines()
                .map(|s| s.chars().collect::<Vec<char>>())
                .collect::<Vec<Vec<char>>>();
            let mut i = lines[0].len();
    
            let mut numbers = vec![];
            let mut total = 0;
            while i > 0 {
                i -= 1;
                let number = [0, 1, 2, 3]
                    .iter()
                    .filter_map(|j| lines[*j][i].to_digit(10))
                    .fold(0, |acc, x| acc * 10 + x);
                if number == 0 {
                    continue;
                }
                numbers.push(number as usize);
                match lines[4][i] {
                    '*' => {
                        total += numbers.iter().product::<usize>();
                        numbers.clear();
                    }
                    '+' => {
                        total += numbers.iter().sum::<usize>();
                        numbers.clear();
                    }
                    ' ' => {}
                    _ => panic!("Unknown operation {}", lines[4][i]),
                }
            }
            assert_eq!(7858808482092, total);
            println!("Total: {}", total);
        }
    

  • source
  • hideshow 2 child comments
  • [–] 1 point 10 months ago*

    Rust

    Finally having some fun with iters. I think part 2 came out nicely once I figured I can rotate the whole input to get numbers that look like ours.

    Q: Anyone have any tips how to reason about the intermediate types in a long iter chain? I'm currently placing dummy maps, and on occasion, even printing the values from them when I get too stuck.

    the code

    use std::fs::File;
    use std::io::{BufReader, Lines};
    
    #[allow(dead_code)]
    pub fn part1(input: Lines<BufReader<File>>) {
        let mut input = input
            .map_while(Result::ok)
            .map(|line| {
                line.split_ascii_whitespace()
                    .map(|s| s.to_string())
                    .collect::<Vec<String>>()
            })
            .collect::<Vec<Vec<String>>>();
    
        let ops = input.pop().unwrap();
        let values = input
            .iter()
            .map(|v| {
                v.iter()
                    .map(|v| v.parse::<i64>().unwrap())
                    .collect::<Vec<i64>>()
            })
            .collect::<Vec<Vec<i64>>>();
    
        let transposed: Vec<Vec<i64>> = (0..values[0].len())
            .map(|i| values.iter().map(|row| row[i]).collect())
            .collect();
    
        let mut sum = 0;
        for i in 0..ops.len() {
            let op: &str = &ops[i];
            match op {
                "+" => {
                    sum += transposed[i].iter().sum::<i64>();
                }
                "*" => {
                    sum += transposed[i].iter().product::<i64>();
                }
                _ => panic!("Invalid operation"),
            }
        }
    
        println!("sum = {}", sum)
    }
    
    #[allow(dead_code)]
    pub fn part2(input: Lines<BufReader<File>>) {
        let mut input = input
            .map_while(Result::ok)
            .map(|line| line.chars().collect::<Vec<char>>())
            .collect::<Vec<Vec<char>>>();
    
        let ops = input
            .pop()
            .unwrap()
            .iter()
            .map(|c| c.to_string())
            .filter(|s| s != " ")
            .collect::<Vec<String>>();
    
        let transposed: Vec<i64> = (0..input[0].len())
            .map(|i| input.iter().map(|row| row[i]).collect())
            .map(|vec: String| vec.trim().to_string())
            .map(|s| {
                if s.len() == 0 {
                    0
                } else {
                    s.parse::<i64>().unwrap()
                }
            })
            .collect();
    
        let groups = transposed
            .into_iter()
            .fold(Vec::new(), |mut acc: Vec<Vec<i64>>, num| {
                if num == 0 {
                    if let Some(last) = acc.last_mut() {
                        if !last.is_empty() {
                            acc.push(Vec::new());
                        }
                    } else {
                        acc.push(Vec::new());
                    }
                } else {
                    if acc.is_empty() {
                        acc.push(Vec::new());
                    }
    
                    acc.last_mut().unwrap().push(num);
                }
    
                acc
            });
    
        let mut sum = 0;
        for i in 0..ops.len() {
            let op: &str = &ops[i];
            match op {
                "+" => {
                    sum += groups[i].iter().sum::<i64>();
                }
                "*" => {
                    sum += groups[i].iter().product::<i64>();
                }
                _ => panic!("Invalid operation"),
            }
        }
    
        println!("sum = {}", sum)
    }
    
    

  • source
  • [–] 1 point 10 months ago (1 child)

    Kotlin

    I'm not fully happy with my parsing today, but oh well. I also thought about just plain building the grid and then rotating it, but "normal input parsing" works too.

    Solution

    class Day06 : Puzzle {
    
        val numsPartOne = mutableListOf<MutableList<Long>>()
        val numsPartTwo = mutableListOf<List<Long>>()
        val ops = mutableListOf<(Long, Long) -> Long>()
    
        override fun readFile() {
            val input = readInputFromFile("src/main/resources/a2025/day06.txt")
            val lines = input.lines().filter { it.isNotBlank() }
    
            // parse part1 input
            for (line in lines.dropLast(1)) {
                for ((c, num) in line.trim().split(" +".toRegex()).withIndex()) {
                    if (numsPartOne.getOrNull(c) == null) numsPartOne.add(mutableListOf())
                    numsPartOne[c].add(num.toLong())
                }
            }
    
            // parse part2 input
            var numList = mutableListOf<Long>()
            for (c in 0..<lines.maxOf { it.length }) {
                var numStr = ""
                for (r in 0..<lines.size - 1) {
                    numStr += lines[r].getOrElse(c) { ' ' }
                }
                if (numStr.isBlank()) {
                    numsPartTwo.add(numList)
                    numList = mutableListOf()
                } else {
                    numList.add(numStr.trim().toLong())
                }
            }
            numsPartTwo.add(numList)
    
            // parse operators
            ops.addAll(
                lines.last().split(" +".toRegex())
                    .map { it.trim()[0] }
                    .map {
                        when (it) {
                            '*' -> { a: Long, b: Long -> a * b }
                            '+' -> { a: Long, b: Long -> a + b }
                            else -> throw IllegalArgumentException("Unknown operator: $it")
                        }
                    }
            )
        }
    
        override fun solvePartOne(): String {
            return numsPartOne.mapIndexed { c, list -> list.reduce { a, b -> ops[c](a, b) } }.sum().toString()
        }
    
        override fun solvePartTwo(): String {
            return numsPartTwo.mapIndexed { c, list -> list.reduce { a, b -> ops[c](a, b) } }.sum().toString()
        }
    }
    

    full code on Codeberg

  • source
  • hideshow 1 child comment
  • [–] 3 points 10 months ago

    I also thought about trying to rotate, but not for very long. Mine would be a bit simpler if I'd done what you did and build the number string and then check if it's blank.

    fun main() {
        val input = getInput(6)
        val output = parseInput2(input)
        var total = 0L
        for ((numbers, operator) in output) {
            when (operator) {
                '+' -> { total += numbers.sum() }
                '*' -> { total += numbers.reduce { acc, number -> acc * number }}
            }
        }
        println(getElapsedTime())
        println(total)
    }
    
    fun parseInput2(input: String): List<Pair<List<Long>, Char>> {
        val rows = input.lines()
            .filter { it.isNotBlank() }
            .map { it.toCharArray() }
        val output: MutableList<Pair<List<Long>, Char>> = mutableListOf()
        val numberRowCount = rows.size - 1
        var isNewProblem = true
        var currentNumbers: MutableList<Long> = mutableListOf()
        var operator = ' '
        for (column in rows[0].indices) {
            if (!isNewProblem && isColumnEmpty(rows, column)) {
                isNewProblem = true
                output.add(currentNumbers to operator)
                continue
            }
            if (isNewProblem) {
                isNewProblem = false
                currentNumbers = mutableListOf()
                operator = rows.last()[column]
            }
            var number = ""
            for (row in 0..<numberRowCount) {
                if (rows[row][column] != ' ') {
                    number += rows[row][column]
                }
            }
            currentNumbers.add(number.toLong())
        }
        if (!isNewProblem) {
            output.add(currentNumbers to operator)
        }
        return output
    }
    
    fun isColumnEmpty(rows: List<CharArray>, column: Int): Boolean {
        for (i in rows.indices) {
            if (rows[i][column] != ' ') {
                return false
            }
        }
        return true
    }
    
  • source
  • parent
  • [–] 1 point 10 months ago

    Rust

    Mainly difficult parsing today.

    View on github

    fn part1(input: String) {
        let mut nums: Vec<Vec<u64>> = Vec::new();
        let mut mul: Vec<bool> = Vec::new();
        for l in input.lines() {
            if l.chars().next().unwrap().is_ascii_digit() {
                let row = l
                    .split_ascii_whitespace()
                    .map(|s| s.parse::<u64>().unwrap())
                    .collect();
                nums.push(row);
            } else {
                mul = l.split_ascii_whitespace().map(|s| s == "*").collect();
            }
        }
        let mut sum = 0;
        for (idx, op_mul) in mul.iter().enumerate() {
            let col = nums.iter().map(|row| row[idx]);
            sum += if *op_mul {
                col.reduce(|acc, n| acc * n)
            } else {
                col.reduce(|acc, n| acc + n)
            }
            .unwrap();
        }
        println!("{sum}");
    }
    
    fn part2(input: String) {
        let grid: Vec<&[u8]> = input.lines().map(|l| l.as_bytes()).collect();
        let n_rows = grid.len() - 1; // Not counting operator row
        let mut op_mul = grid[n_rows][0] == b'*';
        let mut cur = if op_mul { 1 } else { 0 };
        let mut sum = 0;
        for x in 0..grid[0].len() {
            let digits: Vec<u8> = (0..n_rows).map(|y| grid[y][x]).collect();
            if digits.iter().all(|d| *d == b' ') {
                sum += cur;
                op_mul = grid[n_rows][x + 1] == b'*';
                cur = if op_mul { 1 } else { 0 };
                continue;
            }
            let n = String::from_utf8(digits)
                .unwrap()
                .trim()
                .parse::<u64>()
                .unwrap();
            if op_mul {
                cur *= n;
            } else {
                cur += n;
            }
        }
        sum += cur;
        println!("{sum}");
    }
    
    util::aoc_main!();
    
  • source
  • [–] 1 point 10 months ago* (last edited 10 months ago)

    Nim

    The hardest part was reading the part 2 description. I literally looked at it for minutes trying to understand where the problem numbers come from and how they're related to the example input. But then it clicked.

    The next roadblock was that my template was stripping whitespace at the end of the last line, making parsing a lot harder. I've replaced strip() with strip(chars={'\n'}) to keep the trailing space intact.

    Runtime: 1.4 ms 618 ΞΌs

    view code

    type
      AOCSolution[T,U] = tuple[part1: T, part2: U]
    
    proc solve(input: string): AOCSolution[int, int] =
      let lines = input.splitLines()
      let numbers = lines[0..^2]
      let ops = lines[^1]
    
      block p1:
        let numbers = numbers.mapIt(it.splitWhiteSpace().mapIt(parseInt it))
        let ops = ops.splitWhitespace()
        for x in 0 .. numbers[0].high:
          var res = numbers[0][x]
          for y in 1 .. numbers.high:
            case ops[x]
            of "*": res *= numbers[y][x]
            of "+": res += numbers[y][x]
          result.part1 += res
    
      block p2:
        var problems: seq[(char, Slice[int])]
        var ind = 0
        while ind < ops.len:
          let len = ops.skipWhile({' '}, ind+1)
          problems.add (ops[ind], ind .. ind + len - (if ind+len < ops.high: 1 else: 0))
          ind += len + 1
    
        for (op, cols) in problems:
          var res = 0
          for x in cols:
            var num = ""
            for y in 0 .. numbers.high:
              num &= numbers[y][x]
    
            if res == 0:
              res = parseInt num.strip
            else:
              case op
              of '*': res *= parseInt num.strip
              of '+': res += parseInt num.strip
              else: discard
    
          result.part2 += res
    

    Full solution at Codeberg: solution.nim

  • source