▲ 578 ▼ USB inventor explains why the connector was not designed to be reversible (www.pcgamer.com) submitted 3 years ago by ooli@lemmy.world to c/technology@lemmy.world 255 comments fedilink hide all child comments
[–] morriscox@lemmy.world 7 points 3 years ago (1 child) That entry needs a ELI. permalink fedilink source parent hideshow 1 child comment replies: [–] KnightontheSun@lemmy.world 6 points 3 years ago* "In geometry and physics, spinors /spɪnər/ are elements of a complex number-based vector space that can be associated with Euclidean space.[b] A spinor transforms linearly when the Euclidean space is subjected to a slight (infinitesimal) rotation,[c] but unlike geometric vectors and tensors, a spinor transforms to its negative when the space rotates through 360° (see picture). It takes a rotation of 720° for a spinor to go back to its original state. This property characterizes spinors: spinors can be viewed as the "square roots" of vectors (although this is inaccurate and may be misleading; they are better viewed as "square roots" of sections of vector bundles – in the case of the exterior algebra bundle of the cotangent bundle, they thus become "square roots" of differential forms)." Seems pretty self-explanatory to me! /s permalink fedilink source parent
[–] KnightontheSun@lemmy.world 6 points 3 years ago* "In geometry and physics, spinors /spɪnər/ are elements of a complex number-based vector space that can be associated with Euclidean space.[b] A spinor transforms linearly when the Euclidean space is subjected to a slight (infinitesimal) rotation,[c] but unlike geometric vectors and tensors, a spinor transforms to its negative when the space rotates through 360° (see picture). It takes a rotation of 720° for a spinor to go back to its original state. This property characterizes spinors: spinors can be viewed as the "square roots" of vectors (although this is inaccurate and may be misleading; they are better viewed as "square roots" of sections of vector bundles – in the case of the exterior algebra bundle of the cotangent bundle, they thus become "square roots" of differential forms)." Seems pretty self-explanatory to me! /s permalink fedilink source parent