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[–] 27 points 5 months ago* (last edited 5 months ago) (11 children)

phoenix-sweat It is πr^2^ or, equivalently, 1/2 τr^2^

phoenix-think But wait since π is defined in terms of the diameter it should be 1/4 πD^2^ .

phoenix-evidence In fact look at all these quadratic forms

  • distance fallen in a gravitational field: 1/2 gt^2^
  • energy of motion: 1/2 mv^2^
  • speed 1/2 at^2^
  • area of a circle 1/2 τr^2^

phoenix-objection-1phoenix-objection-2 Because when you step up from the linear, one dimensional circumference, and integrate, then the antiderivative should have a 1/2 factor to account for the square when differentiating back. The fact that π cancels this factor, and hides it is to its detriment!

phoenix-smug Read https://www.tauday.com/tau-manifesto again, specifically section 3. τ is how the circumference of a unit circle should be defined since we use the radius and never the diameter. Anything else is revisionism comrade, do better.

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  • [–] 14 points 5 months ago (1 child)

    I have never seen this before, but one of the courses I have to develop curriculum for includes high school level trigonometry, and I am pretty fucking convinced that for learners (especially with LDs in math), the τ circle constant is conceptually easier to understand. The page is absolutely correct that showing a new learner the special angles with τ is a much simpler point of entry than the special angles relative to π (Figures 8 and 10).

    Thanks for sharing!

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  • [–] 8 points 5 months ago

    A class full of young tauists sounds sick and I fully agree that it's conceptually much easier (simply by virtue of being the trivial definition). In application however pi still reigns supreme, so if they use calculators for instance there will be a constant translation effort (remember to multiply with 2, or was it halve it??) that could be frustrating.

    You have the coolest job ever though much props rat-salute

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