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[–] 3 points 9 months ago*

Point taken but….

UML requires:

1 - extensive support from the host kernel above and beyond what is required to execute for regular programs

2 - the guest kernel to be specially compiled to be a UML guest

In other words, even though UML allows a guest Linux kernel to execute as a process on a host Linux kernel, that Linux kernel is not “just a program” like every other user mode application is.

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