Cross products! If you take the cross product of two edges of a face, you get a perpendicular vector for that face. It shouldn’t be too bad to do 20 of those per frame to find if a face is level with the ground (cross product points straight up and/or down depending on how you’re doing them)… now I don’t know about the velocity/acceleration numbers (including rotation)…
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments