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[-] SpaceNoodle@lemmy.world 3 points 2 days ago* (last edited 2 days ago)

Wouldn't that be 3n + 1? n passengers already present, another 2n + 1 enter, resulting in a total of 3n + 1. Doing it in my head, we seem to always end up in a cycle of 4 -> 2 -> 1 -> 4. All of these are < 5, so once we enter that cycle, the number of possible passengers killed is always less than five.

this post was submitted on 11 Feb 2026
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