▲ 182 ▼ I'd do it out of scientific curiosity. (thelemmy.club) submitted 6 months ago by mech@feddit.org to c/mathmemes@lemmy.blahaj.zone 62 comments fedilink hide all child comments
[–] Chais@sh.itjust.works 9 points 6 months ago (1 child) Passengers: 4 > 2 > 1 > 4 So that's better, I guess? permalink fedilink source hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 3 points 6 months ago* (last edited 6 months ago) (3 children) Edit: misread the prompt, below original post is wrong, I apologize! Noe start with three or any odd number :p 3 , 7, 15, 31, 33..... I think only 2^x has the outcome you describe, please correct me if I'm mistaken. permalink fedilink source parent hideshow 6 child comments replies: [–] addison@piefed.social 10 points 6 months ago (1 child) Odd numbers cause double plus one additional passengers to board. So a cycle starting with 3 is a bit different. 3 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1 -> 4 ... permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Edited my response, I misread it. Thank you! permalink fedilink source parent [–] jbrains@sh.itjust.works 5 points 6 months ago (1 child) You misread it, too, did you? 😉 permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Yes! :/ permalink fedilink source parent [–] wonderingwanderer@sopuli.xyz 2 points 6 months ago* (last edited 6 months ago) (1 child) 7→22→11→34→17→52→26→13→40→20→10→5→16→8→4→2→1→4→2→1→4→2→1... Edit: also, 9→28→14→7... And, 15→46→23→70→35→106→53→160→80→40→20→10→5→16→8→4→2→1... Or even, 19→58→29→88→44→22→11→... And lest we forget, 3→10→5→16→8→4→2→1... That covers every odd number below 20. Want me to do 21 and 25, too? Perhaps 27? permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 1 point 6 months ago The trick is to read the prompt. I had 2n+1 are the new number of passengers. Had to reconstruct it from your answer though. Anyway, thanks! permalink fedilink source parent
[–] Scipitie@lemmy.dbzer0.com 3 points 6 months ago* (last edited 6 months ago) (3 children) Edit: misread the prompt, below original post is wrong, I apologize! Noe start with three or any odd number :p 3 , 7, 15, 31, 33..... I think only 2^x has the outcome you describe, please correct me if I'm mistaken. permalink fedilink source parent hideshow 6 child comments replies: [–] addison@piefed.social 10 points 6 months ago (1 child) Odd numbers cause double plus one additional passengers to board. So a cycle starting with 3 is a bit different. 3 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1 -> 4 ... permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Edited my response, I misread it. Thank you! permalink fedilink source parent [–] jbrains@sh.itjust.works 5 points 6 months ago (1 child) You misread it, too, did you? 😉 permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Yes! :/ permalink fedilink source parent [–] wonderingwanderer@sopuli.xyz 2 points 6 months ago* (last edited 6 months ago) (1 child) 7→22→11→34→17→52→26→13→40→20→10→5→16→8→4→2→1→4→2→1→4→2→1... Edit: also, 9→28→14→7... And, 15→46→23→70→35→106→53→160→80→40→20→10→5→16→8→4→2→1... Or even, 19→58→29→88→44→22→11→... And lest we forget, 3→10→5→16→8→4→2→1... That covers every odd number below 20. Want me to do 21 and 25, too? Perhaps 27? permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 1 point 6 months ago The trick is to read the prompt. I had 2n+1 are the new number of passengers. Had to reconstruct it from your answer though. Anyway, thanks! permalink fedilink source parent
[–] addison@piefed.social 10 points 6 months ago (1 child) Odd numbers cause double plus one additional passengers to board. So a cycle starting with 3 is a bit different. 3 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1 -> 4 ... permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Edited my response, I misread it. Thank you! permalink fedilink source parent
[–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Edited my response, I misread it. Thank you! permalink fedilink source parent
[–] jbrains@sh.itjust.works 5 points 6 months ago (1 child) You misread it, too, did you? 😉 permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 2 points 6 months ago Yes! :/ permalink fedilink source parent
[–] wonderingwanderer@sopuli.xyz 2 points 6 months ago* (last edited 6 months ago) (1 child) 7→22→11→34→17→52→26→13→40→20→10→5→16→8→4→2→1→4→2→1→4→2→1... Edit: also, 9→28→14→7... And, 15→46→23→70→35→106→53→160→80→40→20→10→5→16→8→4→2→1... Or even, 19→58→29→88→44→22→11→... And lest we forget, 3→10→5→16→8→4→2→1... That covers every odd number below 20. Want me to do 21 and 25, too? Perhaps 27? permalink fedilink source parent hideshow 2 child comments replies: [–] Scipitie@lemmy.dbzer0.com 1 point 6 months ago The trick is to read the prompt. I had 2n+1 are the new number of passengers. Had to reconstruct it from your answer though. Anyway, thanks! permalink fedilink source parent
[–] Scipitie@lemmy.dbzer0.com 1 point 6 months ago The trick is to read the prompt. I had 2n+1 are the new number of passengers. Had to reconstruct it from your answer though. Anyway, thanks! permalink fedilink source parent