Day 3: Lobby

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[-] Quant@programming.dev 1 points 2 months ago* (last edited 2 months ago)

My original solution for part 1 was just removing the last digit, get the highest number, cut off everything up to and including that first number, get the highest number again.
Once I did part 2 I realized I can just throw in a loop, cut off parts of the end so there's enough numbers left for the subsequent iterations and keep the rest the same.
Now it works for any number of batteries and all you'd need to change is the number after Total! :D

Online pad: AoC-2025-D3

You can even use your own input by uploading a file (make sure it's using LF line endings only with a trailing one at the end) and replacing the example input with this: &rs inf &fo "input-file.txt"

Code

$ 987654321111111
$ 811111111111119
$ 234234234234278
$ 818181911112111
⊜∘⊸≠@\n

Max ← ⊢⊸⍖

Jolt! ← (
  ¯^
  ""
  ⍥(⊙(⤚⊡Max◡↘+₁
      ⊙(⊙↘⤚⋅∘+₁))
    ⊂
  )^
  ⊙⋅◌
)

Total! ← (
  ≡(⋕Jolt!^)
  /+
)

PartOne ← Total!2
PartTwo ← Total!12

⊸PartOne
&pf "Part One: "
&p
PartTwo
&pf "Part Two: "
&p

this post was submitted on 03 Dec 2025

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