▲ 1197 ▼ Math (i.vgy.me) submitted 2 years ago by Zerush@lemmy.ml to c/memes@lemmy.ml 133 comments fedilink hide all child comments
[–] jsomae@lemmy.ml 10 points 2 years ago (3 children) What's the college one mean? permalink fedilink source hideshow 6 child comments replies: [–] kogasa@programming.dev 14 points 2 years ago* (1 child) Stokes' theorem. Almost the same thing as the high school one. It generalizes the fundamental theorem of calculus to arbitrary smooth manifolds. In the case that M is the interval [a, x] and ω is the differential 1-form f(t)dt on M, one has dω = f'(t)dt and ∂M is the oriented tuple {+x, -a}. Integrating f(t)dt over a finite set of oriented points is the same as evaluating at each point and summing, with negatively-oriented points getting a negative sign. Then Stokes' theorem as written says that f(x) - f(a) = integral from a to x of f'(t) dt. permalink fedilink source parent hideshow 2 child comments replies: [–] someacnt_@lemmy.world 1 point 2 years ago Almost the same thing 😏 permalink fedilink source parent [–] Collatz_problem@hexbear.net 6 points 2 years ago* (last edited 2 years ago) It's the most general form of Stokes' theorem that the integral of a differential form over the boundary of an volume and the integral of an exterior derivative of this form over that volume are the same. It covers a lot of classic formulas from the fundamental theorem of calculus to Green's theorem, Gauss' theorem and classic Stokes' theorem. permalink fedilink source parent [–] LittleBorat2@lemmy.ml 4 points 2 years ago Same as high school but fancier? permalink fedilink source parent
[–] kogasa@programming.dev 14 points 2 years ago* (1 child) Stokes' theorem. Almost the same thing as the high school one. It generalizes the fundamental theorem of calculus to arbitrary smooth manifolds. In the case that M is the interval [a, x] and ω is the differential 1-form f(t)dt on M, one has dω = f'(t)dt and ∂M is the oriented tuple {+x, -a}. Integrating f(t)dt over a finite set of oriented points is the same as evaluating at each point and summing, with negatively-oriented points getting a negative sign. Then Stokes' theorem as written says that f(x) - f(a) = integral from a to x of f'(t) dt. permalink fedilink source parent hideshow 2 child comments replies: [–] someacnt_@lemmy.world 1 point 2 years ago Almost the same thing 😏 permalink fedilink source parent
[–] someacnt_@lemmy.world 1 point 2 years ago Almost the same thing 😏 permalink fedilink source parent
[–] Collatz_problem@hexbear.net 6 points 2 years ago* (last edited 2 years ago) It's the most general form of Stokes' theorem that the integral of a differential form over the boundary of an volume and the integral of an exterior derivative of this form over that volume are the same. It covers a lot of classic formulas from the fundamental theorem of calculus to Green's theorem, Gauss' theorem and classic Stokes' theorem. permalink fedilink source parent
[–] LittleBorat2@lemmy.ml 4 points 2 years ago Same as high school but fancier? permalink fedilink source parent